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    A short object of length L is placed along the principal axis of a concave mirror slightly away from the focus of the mirror (u ≈ f). What will be the
    Question

    A short object of length L is placed along the principal axis of a concave mirror slightly away from the focus of the mirror (u ≈ f). What will be the length of the image? (symbols carry their usual meanings)

    A.

    B.

    ​​

    C.


    D.

    ​​

    Correct option is B

    Correct answer is B
    Calculation:
    From the mirror formula:
    1/f = 1/u + 1/v => v = fu/(u - f).
    The magnification (M) is:
    M = -v/u = -(fu/(u - f))/u = -f/(u - f).
    The length of the image is given by:
    Limage = |M| × L => Limage = (f/(u - f)) × L.
    Now, simplifying further:
    Limage = (f2/((u - f)2)) × L.

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