A school has four sections i.e. A, B, C, D in Class IX. The result of annual exams and half yearly exams for the students of these four sections is given in the following table. Study the table carefully and answer the question that follows.

Result	No. of Students
	Section A	Section B	Section C	Section D
Students failed in both exams	27	25	23	26
Students failed in half-yearly but passed in annual exams	17	15	18	19
Students passed in half-yearly but failed in annual exams	6	8	9	7
Students passed in both exams	62	57	60	59

A student is declared pass if he passes in at least one of the two examinations (half-yearly/annual). Which section has the maximum pass percentage?

Correct option is D

Formula Used:

$$\text{Pass Percentage} = \frac{\text{Number of Students Passed}}{\text{Total Number of Students}} \times 100$$

Solution:

the total number of students in each section as follows:

Section A: Total = 27 + 17 + 6 + 62 = 112
Section B: Total = 25 + 15 + 8 + 57 = 105
Section C: Total = 23 + 18 + 9 + 60 = 110
Section D: Total = 26 + 19 + 7 + 59 = 111

The number of students who passed in each section:

Section A: Students passed = 17 + 6 + 62 = 85
Section B: Students passed = 15 + 8 + 57 = 80
Section C: Students passed = 18 + 9 + 60 = 87
Section D: Students passed = 19 + 7 + 59 = 85

The pass percentage for each section:

​$$\text{Section A:} \quad \text{Pass Percentage} = \frac{85}{112} \times 100 = 75.89\%\\ \ \\\text{Section B:} \quad \text{Pass Percentage} = \frac{80}{105} \times 100 = 76.19\%\\ \ \\\text{Section C:} \quad \text{Pass Percentage} = \frac{87}{110} \times 100 = 79.09\%\\ \ \\\text{Section D:} \quad \text{Pass Percentage} = \frac{85}{111} \times 100 = 76.57\%$$ 

The section with the maximum pass percentage is Section C, with a pass percentage of 79.09%