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    A rectangular swimming pool of dimension 20 m x 10m x 2m (length x width x depth) has an inlet with a flowrate of 1 m³/min. If the empty pool takes 10
    Question

    A rectangular swimming pool of dimension 20 m x 10m x 2m (length x width x depth) has an inlet with a flowrate of 1 m³/min. If the empty pool takes 10 hrs time to get completely filled with a leakage rate of 0.13 m³/min, what is the approximate evaporation rate (in m3/min)?

    A.

    0.11

    B.

    0.20

    C.

    0.27

    D.

    0.37

    Correct option is B

    Given:
    Pool dimensions = 20 m × 10 m × 2 m
    Volume of pool = 20 × 10 × 2 = 400 m³
    Inlet flow rate = 1 m³/min
    Filling time = 10 hours = 10 × 60 = 600 minutes
    Leakage rate = 0.13 m³/min
    Need to find: Evaporation rate (in m³/min)

    Formula Used:
    Net volume filled in 600 min = (Inlet Rate−Leakage Rate−Evaporation Rate) × Time = Volume of Pool

    Let evaporation rate be x m³/min.

    Solution:

    (10.13x)×600=400(0.87x)×600=4000.87x=400600=0.6667x=0.870.6667=0.2033\begin{aligned}(1 - 0.13 - x) \times 600 &= 400 \\(0.87 - x) \times 600 &= 400 \\0.87 - x &= \frac{400}{600} = 0.6667 \\x &= 0.87 - 0.6667 = 0.2033\end{aligned}

    ​Final Answer: Approximately 0.20 m³/min → Option (B)

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