arrow
arrow
arrow
A rectangular sheet of 31.4 cm x 10 cm size is rolled across its length to make a cylinder without overlap. What will be the approximate volume of the
Question

A rectangular sheet of 31.4 cm x 10 cm size is rolled across its length to make a cylinder without overlap. What will be the approximate volume of the cylinder?

A.

785 cm³

B.

1570 cm³

C.

3140 cm³

D.

6280 cm³

Correct option is A

Given:
A rectangular sheet of 31.4 cm (length) and 10 cm (width)
It is rolled along its length → the length becomes the circumference of the cylinder
The width becomes the height of the cylinder

Formula:

Circumference=2πr,Volume of cylinder=πr2h \text{Circumference} = 2\pi r, \quad \text{Volume of cylinder} = \pi r^2 h \\[8pt]

Solution:

2πr=31.4=>r=31.42π=31.46.28=5 cm2\pi r = 31.4 \Rightarrow r = \frac{31.4}{2\pi} = \frac{31.4}{6.28} = 5 \, \text{cm} \\

Volume=π×52×10=π×25×10=250π\text{Volume} = \pi \times 5^2 \times 10 = \pi \times 25 \times 10 = 250\pi \\

Volume3.14×250=785 cm3 \text{Volume} \approx 3.14 \times 250 = 785 \, \text{cm}^3

Correct Answer: (A) 785 cm³​​​​​

test-prime-package

Access ‘CSIR NET- GENERAL APTITUDE’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
368k+ students have already unlocked exclusive benefits with Test Prime!
test-prime-package

Access ‘CSIR NET- GENERAL APTITUDE’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
368k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow