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    A rectangle has a width 'a' and length 'b'. If the width is decreased by 20% and the length is increased by 10%, then what is the area of the new rect
    Question

    A rectangle has a width 'a' and length 'b'. If the width is decreased by 20% and the length is increased by 10%, then what is the area of the new rectangle in percentage compared to 'ab'?

    A.

    110%

    B.

    80%

    C.

    88%

    D.

    120%

    Correct option is C


    According to Question :
    We have area of Rectangle =length x breadth
    =b x a
    Given breadth is decreased by 20% so we have new breadth =4a/5
    And length is increased by 10% so new length of rectangle = 11b/10
    Area of Rectangle = 4a/5 x11b/10
    =44ab/50
    So Area new =22ab/25
    Which is less than previous one by 3/25 or 12% and it is 88% percent of previous one.

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