Correct option is B
We use the relationship between wavelength and frequency of an electromagnetic wave:λ×f=cWhere:∙ λ=Wavelength of the wave∙ f=Frequency of the wave∙ c=3×108m/s=Speed of light in vacuum
Given:∙ Lower frequency f1=6MHz=6×106Hz∙ Upper frequency f2=10MHz=10×106HzCalculate minimum wavelength (at highest frequency)λ2=f2c=10×1063×108=30m maximum wavelength (at lowest frequency)λ1=f1c=6×1063×108=50mFinal Answer:Wavelength band=50m to 30m