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    A pipe A can fill a cistern in 12 hours, while pipe B can fill it in 8 hours. In how much time will the cistern be filled, if both pipes A and B
    Question

    A pipe A can fill a cistern in 12 hours, while pipe B can fill it in 8 hours. In how much time will the cistern be filled, if both pipes A and B are opened together?

    A.

    3 hours 26 minutes

    B.

    4 hours 48 minutes

    C.

    4 hours 12 minutes

    D.

    3 hours 54 minutes

    Correct option is B

    Given:

    Pipe A fills cistern in 12 hours.

    Pipe B fills cistern in 8 hours.

    Formula Used:

    Work rate =1Time taken \frac{1}{\text{Time taken}}

    Time =1Combined work rate= \frac{1}{\text{Combined work rate}}

    Solution:

    Work rate of A =112\frac{1}{12}​ per hour.

    Work rate of B =18\frac{1}{8}​ per hour.

    Combined work rate =224+18=524 \frac{2}{24} + \frac{1}{8} = \frac{5}{24}​​

    Time taken together:

    T =1524=245=4.8 hours \frac{1}{\tfrac{5}{24}} = \frac{24}{5} = 4.8 \, \text{hours}

    Convert 0.8 hours into minutes:

    0.8 × 60 = 48 minutes

    The cistern will be filled in 4 hours 48 minutes 

    Alternate method

    LCM of 12 and 8 = 24 units

    A does 2 units/hour, B does 3 units/hour

    Together = 5 units/hour.

    Time =245 \frac{24}5 ​= 4.8 hours = 4h 48m.

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