A person boarded an express train on 30th August 2015 at Ahmedabad for Trivandrum. The train departed from Ahmedabad at 13.30 hours and reached Trivandrum at 7.30 hours on 1st September 2015. If the distance between Ahmedabad and Trivandrum is 2268, the average speed of the train between the two stations was:

Correct option is C

Total distance covered = 2268 Km
Formula used :
Average speed = total distance / total time
Calculation:
Day Number hours of train travel
30 Aug 10.5 hrs
31 Aug 24 hrs
1 Sep 7.5 hrs
Total number of hours train travel = 10.5 + 24 + 7.5 = 42 hrs
So average speed = Total Distance/total time
Average speed = 2268/42
Average speed = 54 km/hr
Average speed = 54 1000/3600 m/s
Average speed = 15 m/s
Average speed = total distance covered/total time to convert Km/hr into m/s multiply by 5/18.