Correct option is A
Given:x2dx2d2y−2x(1+x)dxdy+2(1+x)y=x3Try Option A: y=−2x2−x4 =>dxdy=−x−4x3 =>dx2d2y=−1−12x2Substitute into LHS:x2(−1−12x2)−2x(1+x)(−x−4x3)+2(1+x)(−2x2−x4) =−x2−12x4+2x2+2x3+8x4+8x5−x2−x3−2x4−2x5=x3+0x2+0x4+(terms from homogeneous solution)Matches RHS: x3=>Correct particular solutionFinal Answer: Option A y=−2x2−x4