A mathematics teacher posed the following problems to her students:
A. Simrat pays ₹60,000 as rent for three months. How much will she have to pay for a whole year if the rent per month remains same?
B. Cost of three dozen bananas is ₹45. Calculate the number of bananas that can be purchased for ₹12.50.
C. Joey and Jenny are going to school. Joey started walking before Jenny. When Joey was at the third block, Jenny was at the first block, if bot tare walking with the same speed, then where would Jenny be if Joey is at the ninth block?
Which of the following is correct, with respect to the above three questions?

Correct option is B

Correct Answer: B
Problem A:
Simrat pays ₹60,000 as rent for three months. How much will she have to pay for a whole year if the rent per month remains the same?
Solution:
​$$\text{Rent per month} = \frac{60,000}{3} = 20,000 \\ \ \\\text{Rent for a whole year} = 20,000 \times 12 = 2,40,000 \\$$​​
Explanation: This problem is solved using the unitary method, where we first find the rent per month and then scale it to the whole year (12 months).
Problem B:
Cost of three dozen bananas is ₹45. Calculate the number of bananas that can be purchased for ₹12.50.
Solution:
​$$\text{Cost of 1 dozen} = \frac{45}{3} = 15 \\ \ \\\text{Cost of 1 banana} = \frac{15}{12} = 1.25 \\ \ \\\text{Number of bananas} = \frac{12.50}{1.25} = 10 \\$$​​
Explanation: This problem also uses the unitary method. First, we find the cost per banana and then calculate how many bananas can be bought for ₹12.50.
Problem C:
Joey and Jenny are going to school. Joey started walking before Jenny. When Joey was at the third block, Jenny was at the first block. If both are walking at the same speed, where would Jenny be if Joey is at the ninth block?
Solution:
Difference in blocks = 3 - 1 = 2 blocks
Since both are walking at the same speed, this difference remains constant.
When Joey is at the 9th block, Jenny will be at } 9 - 2 = 7 blocks.
Explanation: This problem involves relative positions, but it doesn't strictly use the unitary method. It's based on the idea that both Joey and Jenny are moving at the same speed, and the relative difference in their positions will remain the same.