A man invested Rs. X at rate of 10% p.a. on compound interest for two years and received an interest of Rs. 1008. If man invested Rs X+1200 (on compound interest) at same rate of interest for same period of time, then find the amount obtained by the man (in Rs.)?

Correct option is B

Equivalent rate of interest for two years at rate of 10% p.a. =$$\left(10 + 10 + \frac{10 \times 10}{100} \right) = 21\%$$​
ATQ, 21X/100=1008
X = 4800 Rs.
New principle = 4800+1200 =6000 Rs.
Required amount = $$6000 + 6000 \times \frac{21}{100} = 7260 \text{ Rs.}$$​