A man covers a distance of 240 kms in 6 hours on the first day, 360 kms in 8 hours on the second day and 450 kms in 6 hours on the third day. Find the average speed per hour covered by him in 3 days.

Correct option is A

Given:

Distance covered on the first day = 240 km, time taken = 6 hours

Distance covered on the second day = 360 km, time taken = 8 hours

Distance covered on the third day = 450 km, time taken = 6 hours

Formula Used:

$$\text{Average Speed} = \frac{\text{Total Distance Covered}}{\text{Total Time Taken}}$$

Solution:

​Total distance covered = 240 km + 360 km + 450 km = 1050 km
Total time taken = 6 hours + 8 hours + 6 hours = 20 hours

Average Speed = $$\frac{\text{1050\\ km} }{\text{20 \\hours}}$$​​

= 52.5 km/h

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