​A man borrows Rs 1024 at the interest rate of 50% per annum but payable half yearly for 2 years. What amount he has to pay back at the end of the loan period if the interest was compound interest?

Correct option is B

Given:
Principal (P) = Rs. 1024
Rate of interest (R) = 50% per annum
Time (T) = 2 years
Compounding = Half-yearly => n = 2

Formula:
​$$A = P \times \left(1 + \frac{R}{100n} \right)^{nT} \\$$​​

Solution:
A = $$1024 \times \left(1 + \frac{50}{100 \times 2} \right)^{2 \times 2} \\$$​​

A = 1024 × (1 + 0.25)⁴
A = 1024 × (1.25)^4
A = 1024 × 2.44140625
A ≈ Rs. 2501.25

Final Answer:
Rs. 2500