A liquid is to be kept in the range of 35°C to 40°C. The range in Fahrenheit scale is (Given: 180°C = 100°F - 32)

Correct option is B

Given:

Temperature range in Centigrade = $$35^\circ$$​ C to $$40^\circ$$​ C

Given relation:

​$$\frac{C}{100} = \frac{F - 32}{180}$$​​

Formula Used:

From the given relation:

F = $$\frac{9}{5}C + 32$$​​

Solution:

For ($$35^\circ$$​ C):

F = $$\frac{9}{5} \times$$​35 + 32 = 63 + 32 = $$95^\circ$$​ F

For ($$40^\circ$$​ C):

F = $$\frac{9}{5} \times 40 + 32 = 72 + 32 = 104^\circ$$​ F

So, range = 95°F - 104°F