A galvanometer with a full scale current of 10 mA has a resistance of 1000 Ω. The multiplying power (the ratio of measured current to galvanometer current) of a 100 Ω shunt with this galvanometer is:

Correct option is B

​​$$\textbf{The multiplying factor or multiplying power (M) is given by:} \\M = 1 + \frac{R_m}{R_s}\textbf{} \\\begin{aligned}& R_s = \text{Shunt resistance}, \\& R_m = \text{Meter (galvanometer) resistance}.\end{aligned}\textbf{} \\\begin{aligned}& I_m = 10 \, \text{mA}, \\& R_m = 1000 \, \Omega, \\& R_s = 100 \, \Omega.\end{aligned}\textbf{} \\\text{Substitute the values into the formula:} \\\begin{aligned}M &= 1 + \frac{1000}{100} \\M &= 1 + 10 = 11\end{aligned}\textbf{}$$​​