A dealer buys two articles X and Y for Rs.600 each. He marks each of them at the same price. He sells X by giving two successive discounts of 25% and 15% and still earns ₹216 as profit. If he sells Y at a single discount of 46%. then what is the profit percentage on Y?

Correct option is D

Given:

Cost price of X and Y = ₹600

Discounts on X = 25% and 15%

Profit on X = ₹216

Discount on Y = 46%

Formula Used:

Successive Discount  = $$d_1 + d_2 - \frac{d_1d_2}{100}$$​​

Profit =$$\frac{Profit \ Percent}{100} \times CP$$​​

SP = CP + Profit

Discount =$$\frac{Discount\ Percent}{100} \times Marked\ Price$$​​

Selling Price = MP - Discount

Solution:

Successive Discount on X  =$$25 + 15 - \frac{(25)(15)}{100}$$​​

= 40 - 3.75

= 36.25%

Let the Marked Price of X and Y be x

Discount $$= \frac{36.25}{100} of x =$$​ 0.3625x

Selling Price = x - 0.3625x = 0.6375

Selling price for X = 600 + 216 = ₹816

And 0.6375x = 816

x = $$\frac{816}{0.6375}$$= ₹1280

Discount on Y = 46% of 1280 = ₹588.8

Selling Price = 1280 - 588.8 = ₹691.2

Profit = 691.2 - 600 = ₹91.2

Profit Percent = $$\frac{91.2}{600} \times 100$$ = 15.2%