Correct option is C
Step 1: Understand the Cube Configuration
The cube is painted on its:
- Two adjacent surfaces: Red.
- Two opposite surfaces (to red): Black.
- Remaining two surfaces: Green.
The cube is divided into 4×4×4=644 \times 4 \times 4 = 644×4×4=64 smaller cubes of equal size.
Step 2: Identify Smaller Cubes with Green Surfaces
Green paint is on two opposite surfaces of the large cube.
Green Faces (Outer Layer of Green Surfaces):
- Each green-painted face is 4×4=164 \times 4 = 164×4=16 cubes.
- Since there are two green-painted faces, the total number of cubes painted with green is:16×2=32cubes.16 \times 2 = 32 \, \text{cubes}.16×2=32cubes.
Overlap of Green Faces:
- The edges of the green faces overlap with the edges of the red and black faces.
- To count only those cubes with at least one green face, we consider only the 32 cubes on the green-painted faces.
Step 3: Check Other Possibilities
Smaller cubes with at least one surface painted green are exactly those on the two green-painted outer faces. No additional overlap or adjustments are needed.
Final Answer:
C) 32 smaller cubes have at least one surface painted with green.