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A cricketer has an average of 68 runs over 9 innings. If he scores 130 runs in the 10th inning, by how many runs (rounded off to the nearest whole num
Question

A cricketer has an average of 68 runs over 9 innings. If he scores 130 runs in the 10th inning, by how many runs (rounded off to the nearest whole number) does his average score increase?

A.

15

B.

10

C.

7

D.

6

Correct option is D

Given:
Average of 9 innings = 68 runs
Runs scored in the 10th inning = 130 runs
Formula Used:
Average = Total RunsNumber of Innings\frac{Total\ Runs}{Number\ of\ Innings}​​
Solution:
Total runs in 9 innings = 68 × 9 = 612
Total runs after 10 innings = 612 + 130 = 742
New average = 74210\frac{742}{10}​ = 74.2
Increase in average = 74.2 - 68 = 6.2
Rounding off to the nearest whole number gives 6.
Final Answer
So the correct answer is (d)

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