Correct option is D
Given:
Pipe A can filled the tank = 9 hours
With leakage Pipe A can fill the tank = 10 hours
Solution
Let the total capacity of the tank = 90 unit
then efficiency of Pipe A = 90\9 = 10 unit /hours
Efficiency of Pipe A and leakage = 90/10 = 9 unit\hours
Efficiency of Leakage = (10 - 9) unit\hours = 1 unit\hours
Then the leakage fill empty the full tanke = 90/1 = 90 hours