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A boat takes 3233 \frac{2}{3}332​ hours in going 40 km upstream and 30 km downstream and the speed of the stream is 7127 \frac{1}{2}721​​ km/h. H
Question

A boat takes 3233 \frac{2}{3} hours in going 40 km upstream and 30 km downstream and the speed of the stream is 7127 \frac{1}{2}​ km/h. How much time (in hours) will the boat take to travel 90 km in still water?

A.

3

B.

3123 \frac{1}{2}​​

C.

4

D.

4124 \frac{1}{2}​​

Correct option is C

Given:

Total time for the combined upstream and downstream journey =  3233\frac{2}{3}​ hours = 113 \frac{11}{3}​ hours

Distance upstream = 40 km

Distance downstream = 30 km

Speed of the stream = 7127 \frac{1}{2}​ km/h = 152 \frac{15}{2}​ km/h

Solution:

Let the speed of the boat in still water be x km/h.

Upstream speed = x - 152\frac{15}{2}​​

Downstream speed = x + 152\frac{15}{2}​​

Now,

40x152+30x+152=113 \frac{40}{x - \frac{15}{2}} + \frac{30}{x + \frac{15}{2}} = \frac{11}{3} ​​

402x152+302x+152=113\frac{40}{\frac{2x - 15}{2}} + \frac{30}{\frac{2x + 15}{2}} = \frac{11}{3}​​

802x15+602x+15=113\frac{80}{2x - 15} + \frac{60}{2x + 15} = \frac{11}{3}​​

80(2x+15)+60(2x15)(2x15)(2x+15)=113 \frac{80(2x + 15) + 60(2x - 15)}{(2x - 15)(2x + 15)} = \frac{11}{3}​​

160x+1200+120x900(2x)2(15)2=113\frac{160x + 1200 + 120x - 900}{(2x)^2 - (15)^2} = \frac{11}{3}​​

280x+3004x2225=113\frac{280x + 300}{4x^2 - 225} = \frac{11}{3}​​

11(4x2 - 225) = 3(280x + 300)

44x2​ - 2475 = 840x + 900

44x2 - 840x - 3375 = 0 

44x2- 990x + 150x - 3375 = 0 

22x(2x - 45) + 75(2x - 45) = 0 

(22x + 75)(2x - 45) = 0 

Speed can't be negative, so

x = 452 km/h\frac{45}{2}\ km/ h  

Now,  time to cover 90 km

Time = 9045/2=4 hours\frac{90}{45/2} = 4 \, \text{hours}​​

The boat will take 4 hours to travel 90 km in still water.

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