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    A block of metal of mass 500 g has a relative density of 2.5. What will be its apparent mass when it is fully immersed in water?
    Question

    A block of metal of mass 500 g has a relative density of 2.5. What will be its apparent mass when it is fully immersed in water?

    A.

    300 g

    B.

    200 g

    C.

    250 g

    D.

    400g

    Correct option is A


    The apparent mass of an object submerged in a fluid is given by:
    Apparent Mass = Actual Mass − Buoyant Force
    Buoyant force is equal to the weight of the displaced fluid:
    Buoyant Force = Mass of Displaced Water
    The mass of displaced water can be found using:
    Mass of Displaced Water=Actual Mass/Relative Density
    Mass of Displaced Water = 500/2.5 = 200 g
    Apparent Mass = 500 – 200 = 300 g

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