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A block of metal of mass 500 g has a relative density of 2.5. What will be its apparent mass when it is fully immersed in water?
Question

A block of metal of mass 500 g has a relative density of 2.5. What will be its apparent mass when it is fully immersed in water?

A.

300 g

B.

200 g

C.

250 g

D.

400g

Correct option is A


The apparent mass of an object submerged in a fluid is given by:
Apparent Mass = Actual Mass − Buoyant Force
Buoyant force is equal to the weight of the displaced fluid:
Buoyant Force = Mass of Displaced Water
The mass of displaced water can be found using:
Mass of Displaced Water=Actual Mass/Relative Density
Mass of Displaced Water = 500/2.5 = 200 g
Apparent Mass = 500 – 200 = 300 g

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