Correct option is D
Given:
Block dimensions = 5 m × 4 m × 2 m.
Tile dimensions = 1 m × 0.5 m × 0.1 m (10 cm = 0.1 m).
Wastage = 10% (so only 90% of the block volume becomes tiles).
Formula:
Volume of block = L × B × H.
Volume of one tile = l × b × h.
Number of tiles (after wastage) = (0.9 × Volume of block) ÷ Volume of one tile.
Solution:
Volume of block = 5 × 4 × 2 = 40 m³.
Volume of one tile = 1 × 0.5 × 0.1 = 0.05 m³.
Usable volume after 10% wastage = 0.9 × 40 = 36 m³.
Number of tiles = 36 ÷ 0.05 = 720.
Correct Answer: (d) 720
