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A bag contains 50 paise, 25 paise and 10 paise coins and the ratio of the numbers of coins is4 : 5 : 9. If the total value of all the coins is R830, t
Question

A bag contains 50 paise, 25 paise and 10 paise coins and the ratio of the numbers of coins is4 : 5 : 9. If the total value of all the coins is R830, then find the number of 25 paise coins inthe bag. 

A.

800

B.

1000

C.

1800

D.

900

Correct option is B

Let's solve this step by step.

Step 1: Define variables

Let the number of 50 paise, 25 paise, and 10 paise coins be 4x, 5x, and 9x, respectively.

Step 2: Calculate total value

  • The total value of 50 paise coins = (4x×504x \times 50​) = 200x paise
  • The total value of 25 paise coins = (5x×255x \times 25​) = 125x paise
  • The total value of 10 paise coins = (9x×109x \times 10​) = 90x paise

The total value of all the coins is given as R830 (or 83000 paise, since 1 Rupee = 100 paise).
So, we set up the equation:
200x+125x+90x=83000200x + 125x + 90x = 83000​​

415x=83000415x = 83000​​

Step 3: Solve for x

x=83000415=200x = \frac{83000}{415} = 200​​

Step 4: Find the number of 25 paise coins

5x=5×200=10005x = 5 \times 200 = 1000​​

Thus, the number of 25 paise coins in the bag is 1000.

Final Answer: (B) 1000

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