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    A bag contains 50 paise, 25 paise and 10 paise coins and the ratio of the numbers of coins is4 : 5 : 9. If the total value of all the coins is R830, t
    Question

    A bag contains 50 paise, 25 paise and 10 paise coins and the ratio of the numbers of coins is4 : 5 : 9. If the total value of all the coins is R830, then find the number of 25 paise coins inthe bag. 

    A.

    800

    B.

    1000

    C.

    1800

    D.

    900

    Correct option is B

    Let's solve this step by step.

    Step 1: Define variables

    Let the number of 50 paise, 25 paise, and 10 paise coins be 4x, 5x, and 9x, respectively.

    Step 2: Calculate total value

    • The total value of 50 paise coins = (4x×504x \times 50​) = 200x paise
    • The total value of 25 paise coins = (5x×255x \times 25​) = 125x paise
    • The total value of 10 paise coins = (9x×109x \times 10​) = 90x paise

    The total value of all the coins is given as R830 (or 83000 paise, since 1 Rupee = 100 paise).
    So, we set up the equation:
    200x+125x+90x=83000200x + 125x + 90x = 83000​​

    415x=83000415x = 83000​​

    Step 3: Solve for x

    x=83000415=200x = \frac{83000}{415} = 200​​

    Step 4: Find the number of 25 paise coins

    5x=5×200=10005x = 5 \times 200 = 1000​​

    Thus, the number of 25 paise coins in the bag is 1000.

    Final Answer: (B) 1000

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