A, B, C have 152, 171 and 266 marbles, respectively. They decide to divide these marbles in parts such that all parts have the same number of marbles. Also, they cannot give or take the marbles. Find the minimum possible number of parts that can  be made.

Correct option is D

Given:

A has 152 marbles
B has 171 marbles
C has 266 marbles
The marbles are to be divided into parts of equal size without giving or taking marbles.

Concept Used:

To divide all marbles into equal parts without transfer, find the HCF (Highest Common Factor) of the three quantities.
Each part will have marbles equal to the HCF.
Minimum number of parts = (Total marbles) ÷ HCF

Solution:

HCF of 152, 171, and 266 = 19
Total marbles = $$\frac{152}{19} +\frac{ 171}{19} + \frac{266}{19}$$ 

Minimum number of parts   = 8 + 9 + 14 = 31