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    ​a, b and c are the sides of a right triangle with c as hypotenuse. The radius r, of the circle which touches the three sides of the triangle is :
    Question

    a, b and c are the sides of a right triangle with c as hypotenuse. The radius r, of the circle which touches the three sides of the triangle is :

    A.

    r=(abc)2r=\frac{\lparen a-b-c\rparen}{2}​​

    B.

    r=(a+bc)2r=\frac{\lparen a+b-c\rparen}{2}​​

    C.

    r=(ab+c)2r=\frac{\lparen a-b+c\rparen}{2}​​

    D.

    r=(a+b+c)2r=\frac{\lparen a+b+c\rparen}{2}​​

    Correct option is B

    Given:

    A right-angled triangle with sides a, b and hypotenuse c.

    The radius r of the incircle is to be determined.

    Formula Used:

    The inradius of a right-angled triangle is given by:

    r =  Area of the triangleSemi-perimeter \frac{\text{Area of the triangle}}{\text{Semi-perimeter}} ​​​

    Solution:

    The semi-perimeter of the triangle:

    s = a+b+c2\frac{a + b + c}{2}​​

    The area of the right triangle:

    A = 12×a×b\frac{1}{2} \times a \times b

    The inradius formula simplifies to:

    r = a+bc2\frac{a + b - c}{2}​

    Option (B) is right.

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