A 3300I250 V, 50 Hz transformer has 75 turns on low voltage winding. Find the number of turns on high voltage winding.

Correct option is B

​$$K = \left( \frac{E_2}{E_1} \right) = \left( \frac{N_2}{N_1} \right) = \left( \frac{I_1}{I_2} \right)\\\textbf{Given:}\\\begin{aligned}\text{The voltage } V_2 \text{ across high voltage winding} &= 3000 \, \text{V} \\\text{The voltage } V_1 \text{ across low voltage winding} &= 250 \, \text{V} \\\text{The Number of turns } N_1 \text{ across low voltage winding} &= 75 \\\text{The number of turns } N_2 \text{ across high voltage winding} &= ?\end{aligned}\\\textbf{Calculation:} \\\text{In an ideal transformer, the voltage across winding is proportional to the number of turns, i.e., In the transformer, } \frac{N_1}{N_2} = \frac{V_1}{V_2} \\\Rightarrow \frac{75}{N_2} = \frac{250}{3000} \\N_2 = 900 \, \text{turns}$$​​