Question


A.

6.125

B.

8.645

C.

7.247

D.

10.245

Correct option is C

(3.321)3+(2.681)3+(1.245)33×3.321×2.681×1.245(3.321)2+(2.681)2+(1.245)2(3.321×2.681)(2.681×1.245)(1.245×3.321)(3.321)2+(2.681)2+(1.245)2(3.321×2.681)(2.681×1.245)(1.245×3.321)a3+b3+c33abc=(a+b+c)(a2+b2+c2abbcca)By using this identity,(3.321+2.681+1.245)[(3.321)2+(2.681)2+(1.245)2(3.321×2.681)(2.681×1.245)(1.245×3.321)](3.321)2+(2.681)2+(1.245)2(3.321×2.681)(2.681×1.245)(1.245×3.321)(3.321+2.681+1.245)=7.247(3.321)^3 + (2.681)^3 + (1.245)^3 - 3 \times 3.321 \times 2.681 \times 1.245 \\\frac{(3.321)^2 + (2.681)^2 + (1.245)^2 - (3.321 \times 2.681) - (2.681 \times 1.245) - (1.245 \times 3.321)}{(3.321)^2 + (2.681)^2 + (1.245)^2 - (3.321 \times 2.681) - (2.681 \times 1.245) - (1.245 \times 3.321)} \\a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca) \\\text{By using this identity,} \\\frac{(3.321 + 2.681 + 1.245) \left[ (3.321)^2 + (2.681)^2 + (1.245)^2 - (3.321 \times 2.681) - (2.681 \times 1.245) - (1.245 \times 3.321) \right]}{(3.321)^2 + (2.681)^2 + (1.245)^2 - (3.321 \times 2.681) - (2.681 \times 1.245) - (1.245 \times 3.321)} \\(3.321 + 2.681 + 1.245) = 7.247​​

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