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​(2250.2×2250.3)(2250.6×2250.4)\frac{(225^{0.2}×225^{0.3})}{(225^{0.6}×225^{0.4} )} (2250.6×2250.4)(2250.2×2250.3)​​is equal to:
Question

(2250.2×2250.3)(2250.6×2250.4)\frac{(225^{0.2}×225^{0.3})}{(225^{0.6}×225^{0.4} )} ​is equal to:

A.

15

B.

1.5

C.

115\frac{1}{15}​​

D.

125\frac{1}{25}​​

Correct option is C

Given:

2250.2×2250.32250.6×2250.4\frac{225^{0.2} \times 225^{0.3}}{225^{0.6} \times 225^{0.4}}  

Concept Used

am×an=am+n aman=amna^m \times a^n = a^{m+n} \\ \ \\ \frac{a^m}{a^n} = a^{m-n}​​

Solution:

2250.2×2250.32250.6×2250.4 =2250.52251.0 =2250.5 =1225 =115\frac{225^{0.2} \times 225^{0.3}}{225^{0.6} \times 225^{0.4}} \\ \ \\ = \frac{225^{0.5} }{225^{1.0}} \\ \ \\ = 225^{-0.5} \\ \ \\ =\frac{1}{\sqrt{225}}\\ \ \\= \frac{1}{15} 

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