If the denominator of a rational number is of the form 2ⁿ×5^m, where n and m are non-negative integers, then what will be the decimal expansion of the number?

Correct option is C

The correct answer is (c) Terminating.
· If the denominator of a rational number can be expressed in the form 2ⁿ×5^m, where n and m are non-negative integers, the decimal expansion of that rational number will always be terminating.
Explanation:
· A rational number will have a terminating decimal expansion if and only if its denominator, in the simplest form, has no prime factors other than 2 and 5.
· For example, the rational number ​ has a denominator 20=2²×5, hence it has a terminating decimal expansion.
Information Booster:
· Non-Terminating but Recurring : This occurs when the denominator has prime factors other than 2 or 5.
· Non-Terminating and Non-Recurring : This type does not apply to rational numbers but to irrational numbers.