​$$\frac{(0.4)^3 + (0.6)^3}{(0.4)^2 - 0.4 \times 0.6 + (0.6)^2}$$​ has the value-

Correct option is B

Given:

​$$\frac{(0.4)^3 + (0.6)^3}{(0.4)^2 - 0.4 \times 0.6 + (0.6)^2}$$

Concept Used:

$$\begin{array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\\hline \text{Brackets} &[],{}, () \\ \hline \text{Orders, of} & (power), √ (root) , of \\ \hline \text{Division}& ÷ \\ \hline \text{Multiplication} & × \\ \hline \text{Addition} & + \\ \hline \text{Subtraction} & - \\\hline \end{array}$$​

Solution:

​$$\frac{(0.4)^3 + (0.6)^3}{(0.4)^2 - 0.4 \times 0.6 + (0.6)^2}$$

= $$\frac{0.64 + 0.216}{0.16 - 0.4 \times 0.6 + 0.36}$$

= $$\frac{0.64 + 0.216}{0.16 - 0.24 + 0.36}$$

= $$\frac{0.280}{0.52 - 0.24}$$

= $$\frac{0.280}{0.280}$$

= 1

Thus, the correct answer is (b).