Are you preparing for the Odisha Sub-Ordinate Staff Selection Commission (OSSSC) Accountant or Data Entry Operator (DEO) exams? Mastering Reasoning is crucial for success in these competitive exams. To assist you in your preparation, we’ve compiled a list of the top 20 Reasoning Multiple Choice Questions (MCQs) that commonly appear in these exams. Let’s dive in:
Top 20 Reasoning Awareness MCQS For OSSSC Accountant, DEO
Directions (1-3): Select the related word / letter / numbers from the given alternatives:
Q1. Summer : Aestivation : : Winter : ?
(a) Cache
(b) Hibernation
(c) Survival
(d) Activation
S1. Ans.(b)
Sol. Aestivation during summer as hibernate during winters.
Q2. BFJ : NRV : : DHL : ?
(a) PTA
(b) PTX
(c) KQS
(d) MQV
S2. Ans.(b)
Sol.
+12/+12/+12 series.
Q3. 5 : 30 : : 7 : ?
(a) 54
(b) 50
(c) 49
(d) 56
S3. Ans.(d)
Sol.
Directions (4-6):Find the odd word / letters / number from the given alternatives.
Q4. (a) Throat
(b) Eye
(c) Ear
(d) Skin
S4. Ans.(a)
Sol.
Except (A), all are sensory organs.
Q5. (a) ABBC
(b) PQQR
(c) WYYZ
(d) KLLM
S5. Ans.(c)
Sol. +1, +0, +1 series.
Q6. (a) 16
(b) 4
(c) 2
(d) 36
S6. Ans.(c)
Sol.
2 is a prime number.
Q7. From the given alternatives, select the word which CANNOT be formed using the letters of the given word.
Reprehensible
(a) Repair
(b) Hen
(c) Rise
(d) Ripe
S7. Ans.(a)
Sol.
Repair because there is no ‘a’ in the given word
Q8. In a certain code language, ‘x’ represents ‘+’, ‘÷’ represents ‘x’, ‘-‘ represents ‘÷’ and ‘+’ represents ‘-‘. Find out the answer to the following question.
20 ÷ 12 – 30 + 10 x 10 = ?
(a) 8
(b) 25
(c) 14
(d) 21
S8. Ans.(a)
Sol.
20 ÷ 12 – 30 + 10 × 10
↓
20 × 12 ÷ 30 -10 + 10
= 8
Q9. The following equation is incorrect. Which two signs should be interchanged to correct the equation?
32 ÷ 16 – 5 x 8 + 2 = 13
(a) + and ÷
(b) + and x
(c) – and +
(d) ÷ and x
S9. Ans.(b)
Sol.
32 ÷ 16 – 5 × 8 + 2 = 13
Interchanging + and ×
32 ÷ 16 – 5 + 8 × 2 = 2 – 5 + 16 = 13
Q10. If 6@16 = 11, 2@14 = 8 and 8@8 = 8, then find the value of 10@18 = ?
(a) 4
(b) 6
(c) 12
(d) 14
S10. Ans.(d)
Sol.
Q11. If CAB = 13 and FEED = 41, then FADE =?
(a) 33
(b) 39
(c) 41
(d) 29
S11.Ans. (a)
Sol. Given CAB = (3+1+2) x 2 + 1 = 13
FEED = (6+5+5+4) x 2 + 1 = 41
FADE = (6+1+4+5) x 2 + 1 = 33
Q12. If in a certain code ‘OPERATION’ is written as ‘BWDATXPBJ’ and ‘PARENT’ is written as ‘WTADJX’, how will ‘ORIENT’ be written in that code language?
(a) PSJFOU
(b) BAPDJX
(c) BPADJX
(d) BWPDJX
S12.Ans. (b)
Sol. As, second letter of all option is different So,
R in OPERATION is coded as A in BWDATXPBJ
A is given in option (B) so, it is the correct answer.
Q13. If in a certain code, EDITION is written as VWRGRLM, then which word will be coded as SLMVHGB?
(a) HAUGHTY
(b) AMNESTY
(c) EDITORS
(d) HONESTY
S13.Ans. (d)
Sol. Logic is: All letters are coded as the opposite alphabetical position.
So, HONESTY will be written as SLMVHGB
Q14. Anjali says, “He is the only son of the father of my sister’s brother.” How is that person related to Anjali?
(a) Uncle
(b) Cousin
(c) Brother
(d) Father
S14.Ans. (c)
Sol. The father of Anjali’s sister’s brother means father of Anjali.
Only son of Anjali’s father means brother of Anjali.
Q15. From the given alternative words, select the word which cannot be formed using the letters of the given word:
COURAGEOUS
(a) COURSE
(b) GRACE
(c) SECURE
(d) ARGUE
S15.Ans. (c)
Sol. There is only one ‘E’ in the given word. Therefore, the word
SECURE cannot be formed.
Q16. In a code language, if ‘SOLID’ is written as ‘8415323’, then how will ‘LUCID’ be written in that language?
(a) 15524323
(b) 14524323
(c) 15424322
(d) 15423322
S16.Ans. (a)
Sol. Consonants are replaced by the place value of the opposite alphabet.
And vowels are replaced by the place value of the alphabet in vowel
Alphabet, (A-1,E-2,I-3,O-4,U-5.)
LUCID
L (opposite alphabet)=O=15
U(vowel)=5
C(opposite alphabet) =X=24
I(vowel)=3
D(opposite alphabet)=W=23
Q17. If A is coded as ‘+’, B is coded as ‘x’, C is coded as ‘÷’ and D is coded as ‘-‘, then 18 A 6 B 2 C 16 B 4 D 21 =?
(a) 2
(b) -1
(c) 0
(d) 1
S17.Ans. (c)
Sol. 18 A 6 B 2 C 16 B 4 D 21
After coding,
18+6*2/16*4-21
= 18+6*2/16*4-21
= 18+3-21=0
Q18. In a certain code language ,’apple’ is called ‘pear’, ‘pear’ is called ‘orange’ , ‘orange’ is called ‘guava’ and ‘guava’ is called ‘melon’. In this language, which one of the following will be a citrus fruit?
(a) Pear
(b) Melon
(c) Guava
(d) Orange
S18.Ans. (c)
Sol. Since we know ORANGE is a citrus fruit and it is called GUAVA in the given languageTherefore the citrus fruit as per the condition is GUAVA.
Q19. If each of the letters of the English alphabet is assigned an odd numerical value beginning with A = 1, B = 3 and so on, then what will be the total value of the letters of the word CARDINAL?
(a) 114
(b) 116
(c) 110
(d) 119
S19.Ans. (b)
Sol.
Logic is : 2(alphabetical position)-1
So, C= 2*3-1=5,
Similarly,
A=1, R=35, D=7, I=17,
N=27,A=1,L=23
Code for CARDINALS is 5+1+35+7+17+27+1+23=116.
Q20. In a certain code language,
‘dish is tasty’ is written as ‘lam kam dam’,
‘it is sweet’ is written as ‘ram sam kam’, and
‘It ate dish’ is written as ‘ram dam pam’,
Then how would ‘tasty sweet’ be written in this language?
(a) lam ram
(b) sam dam
(c) sam kam
(d) lam sam
S20.Ans. (d)
Sol. ‘dish is TASTY’ is written as LAM kam dam
‘it is SWEET’ is written as LAM kam dam
‘It ate dish’ is written as ram dam pam
So,code for ‘tasty’ is lam and for ‘sweet’ is sam.
So, ‘tasty’ sweet’ coded as ‘lam sam’
