The “Top 15 Arithmetic MCQs for Odisha Police Constable Exam” covers essential mathematical concepts critical for competitive exam preparation. This set includes questions from various topics such as Pipe & Cistern, Number System, Time & Work, Simple Interest (SI) & Compound Interest (CI), Calendar Days Calculation, Profit & Loss, Simplification, Probability, Time & Distance, Mensuration, LCM & HCF, and Boat & Stream. Each question is crafted to challenge candidates’ problem-solving skills and enhance their arithmetic proficiency. These MCQs offer a comprehensive approach to mastering key topics, providing step-by-step solutions and detailed explanations to aid in exam readiness.
Top 15 Arithmetic MCQs For Odisha Police Constable
Q1. Two pipes can fill a tank in 12 minutes and 16 minutes respectively. If both are opened together, how much time will it take to fill the tank?
(a) 9.6 minutes
(b) 10.4 minutes
(c) 7.5 minutes
(d) 8 minutes
Ans: : (a) 9.6 minutes
Sol:
Rate of Pipe 1 = 1/12, Rate of Pipe 2 = 1/16
Combined rate = 1/12 + 1/16 = 4/48 + 3/48 = 7/48
Time = 48/7 = 9.6 minutes
Q2. What is the least number which when divided by 6, 7, and 8 leaves a remainder of 4?
(a) 100
(b) 156
(c) 124
(d) 140
Ans: : (d) 140
Sol:
LCM of 6, 7, and 8 is 168. Required number = 168 – 4 = 164.
Q3. The difference between a number and its three-fifth is 40. What is the number?
(a) 100
(b) 75
(c) 90
(d) 120
Ans: : (a) 100
Sol:
Let the number be x. Then, x – (3/5)x = 40
=> (2/5)x = 40
=> x = (40 × 5)/2 = 100.
Q4. If 12 men can complete a work in 8 days, how many men are required to finish the same work in 6 days?
(a) 10
(b) 14
(c) 16
(d) 18
Ans: : (c) 16
Sol:
Work = Men × Days, so required men = (12 × 8) / 6 = 16 men.
Q5. Find the simple interest on ₹1500 at 8% per annum for 3 years.
(a) ₹360
(b) ₹480
(c) ₹300
(d) ₹450
Ans: : (b) ₹360
Sol:
Simple Interest = (P × R × T) / 100 = (1500 × 8 × 3) / 100 = ₹360.
Q6. A boat takes 8 hours to travel 48 km upstream. If the speed of the stream is 2 km/h, what is the speed of the boat in still water?
(a) 6 km/h
(b) 8 km/h
(c) 10 km/h
(d) 12 km/h
Ans: (b) 8 km/h
Sol:
Upstream speed = 48/8 = 6 km/h. Speed of boat in still water = (Upstream speed + Speed of stream) = 6 + 2 = 8 km/h.
Q7. A trader marks his goods at 20% above the cost price and gives a discount of 10%. What is his profit percentage?
(a) 8%
(b) 10%
(c) 12%
(d) 15%
Ans: : (a) 8%
Sol:
SP = 110% of CP after a 10% discount. Profit = 110% – 100% = 8%.
Q8. A shopkeeper buys an article for ₹200 and sells it at a loss of 10%. What is the selling price?
(a) ₹190
(b) ₹180
(c) ₹175
(d) ₹160
Ans: : (b) ₹180
Sol:
Selling Price = Cost Price × (1 – Loss%) = 200 × (1 – 0.10) = ₹180.
Q9. Simplify: (15 + 20 ÷ 4 × 3) – 5.
(a) 30
(b) 22.5
(c) 32
(d) 28
Ans: : (d) 28
Sol:
Using BODMAS: 20 ÷ 4 = 5, 5 × 3 = 15, (15 + 15) – 5 = 28.
Q10. Simplify: (72 ÷ 8) + (45 ÷ 5) – (16 ÷ 4).
(a) 16
(b) 14
(c) 18
(d) 12
Ans: : (a) 16
Sol:
72 ÷ 8 = 9, 45 ÷ 5 = 9, 16 ÷ 4 = 4, so 9 + 9 – 4 = 16.
Q11. A bag contains 5 red and 3 blue balls. If one ball is drawn at random, what is the probability that it is red?
(a) 5/8
(b) 3/8
(c) 1/2
(d) 7/8
Ans: : (a) 5/8
Sol:
Probability = Favorable outcomes / Total outcomes = 5/8.
Q12. A car covers 120 km in 2 hours. What is its speed?
(a) 40 km/hr
(b) 60 km/hr
(c) 80 km/hr
(d) 50 km/hr
Ans: : (b) 60 km/hr
Sol:
Speed = Distance / Time = 120/2 = 60 km/hr.
Q13. What is the volume of a cube with a side length of 5 cm?
(a) 100 cm³
(b) 125 cm³
(c) 150 cm³
(d) 200 cm³
Ans: : (b) 125 cm³
Sol:
Volume of a cube = side³ = 5³ = 125 cm³.
Q14. The area of a rectangle is 240 cm². If the length is 15 cm, find the breadth.
(a) 12 cm
(b) 14 cm
(c) 16 cm
(d) 18 cm
Ans: : (a) 12 cm
Sol:
Area = Length × Breadth, so Breadth = Area / Length = 240/15 = 12 cm.
Q15. Find the LCM of 12 and 15.
(a) 30
(b) 45
(c) 60
(d) 90
Ans: : (c) 60
Sol:
LCM of 12 and 15 is the smallest number divisible by both, which is 60.
