Top 15 Arithmetic MCQs For Odisha Police Constable
Q1. What is the least number which, when divided by 15, 20, and 25, leaves a remainder of 4 in each case?
(a) 304
(b) 304
(c) 254
(d) 154
Ans: (a) 304
Sol:
LCM of 15, 20, and 25 = 300.
Required number = LCM + remainder = 300 + 4 = 304.
Q2. Find the LCM of 72, 108, and 90.
(a) 1260
(b) 720
(c) 2160
(d) 360
Ans: (b) 720
Sol:
Prime factorizations:
72 = 2³ × 3²,
108 = 2² × 3³,
90 = 2 × 3² × 5.
LCM = 2³ × 3³ × 5 = 720.
Q3. Find the HCF of 64, 112, and 144.
(a) 12
(b) 16
(c) 32
(d) 8
Ans: (b) 16
Sol:
Prime factorizations:
64 = 2⁶,
112 = 2⁴ × 7,
144 = 2⁴ × 3².
HCF = 2⁴ = 16.
Q4. What is the square of 48?
(a) 1024
(b) 2025
(c) 2304
(d) 1444
Ans: (c) 2304
Sol:
48 × 48 = 2304.
Q5. Find the square root of 1225.
(a) 25
(b) 35
(c) 45
(d) 55
Ans: (b) 35
Sol:
35 × 35 = 1225. Therefore, √1225 = 35.
Q6. What is the cube of 9?
(a) 629
(b) 819
(c) 729
(d) 609
Ans: (c) 729
Sol:
9 × 9 × 9 = 729.
Q7. What is the cube root of 512?
(a) 6
(b) 7
(c) 8
(d) 9
Ans: (c) 8
Sol:
8 × 8 × 8 = 512, so ∛512 = 8.
Q8. What is 30% of 450?
(a) 135
(b) 125
(c) 145
(d) 130
Ans: (a) 135
Sol:
(30/100) × 450 = 135.
Q9. A man spends 75% of his income. If his income is ₹40,000, how much does he save?
(a) ₹10,000
(b) ₹9,000
(c) ₹11,000
(d) ₹13,000
Ans: (a) ₹10,000
Sol:
Savings = 100% – 75% = 25%.
Savings = (25/100) × 40,000 = ₹10,000.
Q10. Find the average of 15, 25, 35, 45, and 55.
(a) 35
(b) 30
(c) 40
(d) 25
Ans: (a) 35
Sol:
Average = (15 + 25 + 35 + 45 + 55) / 5 = 175 / 5 = 35.
Q11. The average age of 10 people in a room is 30. If one person leaves, and the average drops to 29, what is the age of the person who left?
(a) 38
(b) 40
(c) 39
(d) 45
Ans: (c) 39
Sol:
Sum of ages of 10 people = 10 × 30 = 300,
Sum of ages of 9 people = 9 × 29 = 261,
Age of the person who left = 300 – 261 = 39.
Q12. Find the simple interest on ₹10,000 for 3 years at 6% per annum.
(a) ₹2,000
(b) ₹1,800
(c) ₹2,500
(d) ₹1,600
Ans: (b) ₹1,800
Sol:
SI = (P × R × T) / 100 = (10000 × 6 × 3) / 100 = ₹1,800.
Q13. A sum of ₹5,000 becomes ₹6,500 in 5 years at simple interest. Find the rate of interest.
(a) 5%
(b) 4%
(c) 6%
(d) 3%
Ans: (a) 5%
Sol:
SI = ₹6,500 – ₹5,000 = ₹1,500,
Rate = (SI × 100) / (P × T) = (1500 × 100) / (5000 × 5) = 5%.
Q14. Find the compound interest on ₹12,000 at 8% per annum for 2 years, compounded annually.
(a) ₹1,996.8
(b) ₹1,880.6
(c) ₹2,300
(d) ₹2,250
Ans: (a) ₹1,996.8
Sol:
CI = P (1 + R/100)ⁿ – P = 12000(1 + 8/100)² – 12000 = ₹1,996.8.
Q15. What is the compound interest on ₹20,000 at 10% per annum for 3 years, compounded annually?
(a) ₹6,210
(b) ₹6,200
(c) ₹6,231
(d) ₹6,250
Ans: (c) ₹6,231
Sol:
CI = P (1 + R/100)ⁿ – P = 20000(1 + 10/100)³ – 20000 = ₹6,231.
