Odia govt jobs   »   How to Prepare Arithmetic for OSSSC...

How to Prepare Arithmetic for OSSSC LSI, Forester, Forest Guard?

Competitive exams such as those conducted by the Odisha Sub-ordinate Staff Selection Commission (OSSSC) for positions like LSI (Livestock Inspector), Forester, and Forest Guard often include a significant portion dedicated to Arithmetic. To excel in these exams, it is crucial to have a solid understanding of various arithmetic topics. Let’s delve into some key arithmetic topics and work through examples to enhance your preparation.

Understanding OSSSC LSI, Forester, FG Arithmetic Syllabus

  • Understanding the exam syllabus for the Arithmetic language component in the OSSSC LSI, Forester, FG Recruitment is essential to plan your preparation effectively.
  • Begin by thoroughly understanding the Arithmetic syllabus for the recruitment exam. This will help you identify the specific topics and areas you need to focus on.
  • Here’s a breakdown of the key topics typically included in the syllabus:
Subject Topic
Arithmetic
  • SI and Compound Interest
  • Volumes
  • Odd Man Out
  • Quadratic Equations
  • Probability
  • Time and Work Partnership
  • Ratio and Proportion
  • Boats and Streams
  • Simple Interest
  • Time and Distance
  • Problems on Trains
  • Areas
  • Races and Games
  • Numbers and Ages
  • Mixtures and Allegations
  • Mensuration
  • Permutations and Combinations
  • Problems on L.C.M and H.C.F
  • Pipes and Cisterns
  • Percentages
  • Simple Equations
  • Problems on Numbers
  • Averages
  • Indices and Surds
  • Profit and Loss
  • Simplification and Approximation

Understanding OSSSC LSI, Forester, FG Arithmetic Exam Pattern

  •  The written test for LSI, Forester, FG consists of objective-type multiple-choice questions only.
  • This exam has negative marking, with a penalty of 0.25 marks for each wrong answer in the written test.
  • OSSSC LSI, Forester, and Forest Guard Exam Pattern 2023: The OSSSC LSI, Forester, and Forest Guard written exam will consist of multiple choice questions.
  • The total duration of the written test will be 2 1/2 hours and the maximum marks will be 150.
Post Name Full Marks No. Of Questions No. Of Questions in Arithmetic
LSI, Forester, FG 150 150 25

General Tips:

  • Maintain a consistent study schedule.
  • Stay disciplined and avoid procrastination.
  • Take short breaks during study sessions to stay refreshed.
  • Keep a positive attitude and stay confident in your abilities.

1. Simple Interest:

Question 1: If the principal is Rs. 2000, the rate of interest is 4% per annum, and the time is 3 years, what is the simple interest?

A. Rs. 240
B. Rs. 250
C. Rs. 260
D. Rs. 270

Solution 1:

Correct Answer: A. Rs. 240

The formula for calculating Simple Interest (SI) is:

where:

Given the values:

  • Principal () = Rs. 2000,
  • Rate of Interest () = 4% per annum,
  • Time () = 3 years.

Substitute these values into the formula:

Calculate the result: =(2000×4×3)/100

Therefore, the Simple Interest (SI) on a principal of Rs. 2000 at a rate of 4% per annum for 3 years is Rs. 240.

Question 2: A sum of Rs. 3000 is invested at an interest rate of 6% per annum. Find the simple interest after 2 years.

A. Rs. 300
B. Rs. 330
C. Rs. 360
D. Rs. 380

Solution 2:

Correct Answer: C. Rs. 360

The formula for calculating Simple Interest (SI) is:

where:

Given the values:

  • Principal () = Rs. 3000,
  • Rate of Interest () = 6% per annum,
  • Time () = 2 years.

Substitute these values into the formula:

Calculate the result:

(3000×6×2)/100

Therefore, the Simple Interest (SI) on a principal of Rs. 3000 at a rate of 6% per annum for 2 years is Rs. 360.

2. Compound Interest:

Question 3: Calculate the compound interest on Rs. 5000 at an annual rate of 8%, compounded annually for 2 years.

A. Rs. 820
B. Rs. 840
C. Rs. 860
D. Rs. 880

Solution 3:

Correct Answer: B. Rs. 840

The formula for calculating Compound Interest (CI) is given by:

A= P(1+r/100)^t

where:

  • is the principal amount,
  • is the rate of interest per annum,
  • is the time in years, and
  • is the amount after years.

The Compound Interest () is then calculated as:

Given the values:

  • Principal () = Rs. 5000,
  • Rate of Interest () = 8% per annum,
  • Time () = 2 years.

Substitute these values into the formula to find the amount after 2 years ():

=5000(1+8/100)^2

≈5832

Now, calculate the Compound Interest ():

=5832−5000

Therefore, the Compound Interest (CI) on Rs. 5000 at an annual rate of 8%, compounded annually for 2 years, is Rs. 832.

Question 4: If the compound interest on a sum of money is Rs. 1200 at an annual rate of 10%, find the principal amount. The interest is compounded annually for 3 years.

A. Rs. 3000
B. Rs. 4000
C. Rs. 5000
D. Rs. 6000

Solution 4:

Correct Answer: A. Rs. 3000

  • Rate of Interest () = 10% per annum,
  • Time () = 3 years.

We need to find the Principal (). Rearrange the formula to solve for :

A= P(1+r/100)^t

Substitute the values into the formula:

=1200(1+10/100)^3

=

Therefore, the principal amount is approximately Rs. 902.98.

3. Ratio and Proportion:

Question 5: If the ratio of the lengths of two sides of a rectangle is 2:5 and the perimeter is 70 cm, what is the length of the longer side?

A. 25 cm
B. 30 cm
C. 35 cm
D. 40 cm

Solution 5:

Let the sides be 2x and 5x.

The perimeter () of a rectangle is given by the formula:

In this case, the perimeter is given as 70 cm:

70=2×(l+b)

Simplifying this equation, we find:

Solving for :

Now, we can find the length of the longer side ():

Length of the longer side=5×5=25 cm

So, option A. 25 cm is the correct answer.

Correct Answer: A. 25 cm

Question 6: If 20% of a number is equal to 25, what is 30% of that number?

A. 37.5
B. 45
C. 50
D. 55

Solution 6:

Let the number be .
20/100(x)=25

x=25*100/20=37.5

Correct Answer: A. 37.5

4. Time and Work:

Question 7: A can complete a work in 15 days, and B can complete the same work in 20 days. In how many days will they together complete the work?

A. 6
B. 8
C. 10
D. 12

Solution 7:

Work done by A in 1 day=1/15

Work done by B in 1 day=1/20

Work done by A and B in 1 day=1/15+1/20=4/60=1/15

Days 

15

Correct Answer: A. 6

Question 8: A pipe can fill a tank in 6 hours, and another pipe can empty the tank in 8 hours. If both pipes are opened together, how long will it take to fill the tank?

A. 4 hours
B. 5 hours
C. 6 hours
D. 7 hours

Solution 8: Rate of filling of the first pipe=1/6

Rate of emptying of the second pipe=1/8

Net rate when both pipes are opened together=1/6−1/8=1/24

Time to fill the tank=1

Net rate=24

Correct Answer: C. 6 hours

5. Ages:

Question 9: The sum of the ages of A and B is 45 years. If A is 15 years older than B, what is the age of B?

A. 15 years
B. 20 years
C. 25 years
D. 30 years

Solution 9: Let the age of B be .

Let’s denote the age of B as . Since A is 15 years older than B,

the age of A is x+15.

The sum of their ages is given as 45 years:

Combine like terms:

2x+15=45

Subtract 15 from both sides:

Divide both sides by 2:

So, the age of B () is 15 years.

Correct Answer: A. 15 years

Question 10:The present ages of A, B, and C are in the ratio 5:7:9. If the sum of their ages is 105 years, what is C’s present age?

A. 27 years
B. 36 years
C. 45 years
D. 54 years

Solution 10:

Let’s denote the common ratio as . The present ages of A, B, and C can then be expressed as 5, 7, and 9 respectively.

The sum of their ages is given as 105 years:

Combine like terms:

21x=105

Now that we know , we can find the age of C ():

Age of C=9×5=45

So, C’s present age is 45 years.

OJPT

name

Official Links
Adda247 Arithmetic website Click Here
Official website osssc.gov.in
Download ADDA247 Arithmetic APP Click Here