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UPTET 2019 Important Mathematics Questions | 14th December 2019

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UPTET Exam Practice Mathematics Questions

Dear Students!!! There is most general as well as a scoring section in all the competitive entrance examinations in the teaching field i.e Mathematics“.Because in this section only one thing is work i.e your accuracy and that could be nourished with the daily practice. With a proper system, Study Notes, Quizzes, Vocabulary one can quiet his/her nerves and exceed expectations in the blink of an eye. So, for this, we are providing you the daily quiz for all teaching exams i.e TET Exam 2019DSSSBKVSSTET Exam.

Q1. Rs. 2000 amounts to Rs. 2226.05 in 2 years at compound interest what will be the rate of interest?
2 वर्षों में 2000 रु चक्रवृद्धि ब्याज से 2226.05 रु हो जाते हैं. ब्याज दर क्या होगी?
(a) 5%
(b) 5.25%
(c) 6%
(d) 5.5%

Q2. The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is
एक आयत की लंबाई और चौड़ाई के बीच का अंतर 23 मीटर है. यदि इसकी परिधि 206 मीटर है, तो इसका क्षेत्रफल होगा
(a) 1520 m²
(b) 2420 m²
(c) 2480 m²
(d) 2520 m²

Q3. What would be the area of a rectangle whose area is equal to the area of a circle of radius 7 cm?
एक आयत का क्षेत्रफल क्या होगा जो 7 सेमी त्रिज्या वाले वृत्त के क्षेत्रफल के बराबर है?
(a) 77 cm²
(b) 154 cm²
(c) 184 cm²
(d) 180 cm²

Q4. The area of Rhombus with side 13cm and one diagonal 10cm will be
एक सम-चतुर्भुज जिसकी एक भुजा 13 सेमी और एक विकर्ण 10सेमी है उसका क्षेत्रफल होगा:
(a) 140 cm²
(b) 120 cm²
(c) 130 cm²
(d) 110 cm²

Q5. The volume and surface area of sphere radius 10.5 cm.
10.5 सेमी त्रिज्या वाले गोले का आयतन और पृष्ठीय क्षेत्रफल होगा:
(a) 4851 cm³ and 1386 cm²/4851 सेमी³ और 1386 सेमी ²
(b) 4451 cm³ and 1376 cm²/4451 सेमी ³ और 1376 सेमी ²
(c) 1376 cm³ and 4851 cm²/1376 सेमी ³ और 4851 सेमी ²
(d) 4450 cm³ and 1320 cm²/4450 सेमी ³ और 1320 सेमी ²

Q6. The product of two whole numbers is 1500 and their HCF is 10. Find the LCM.
दो पूर्ण संख्याओं का गुणनफल 1500 है और उनका HCF 10 है. LCM ज्ञात कीजिए.
(a) 148
(b) 150
(c) 160
(d) 147

Q7. 24.424 + 5.656 + 1.131 + 0.089 = ?
(a) 31.003
(b) 31.3
(c) 31.0003
(d) 31.03

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Solutions

S1. Ans.(d)

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S2. Ans.(d)
Sol. Length = L, Breadth = B
L – B = 23       …(i)
Perimeter of rectangle = 2(l + b)
206 = 2 (l + b)
103 = l + B          …(ii)
By solving (i) and (ii)

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2B = 80
B = 40     …(i)
L – 40 = 23
L = 63     …(ii)
Area = L × B
= 63 × 40
= 2520 m²

S3. Ans.(b)
Sol. radius = 7
Area of circle = πr²

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Area of circle = Area of rectangle
So, Area of rectangle = 154 cm²

S4. Ans.(b)
Sol.
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(AO)² + (OB)² = AB²
AO² + 25 = 169
AO² = 169 – 25
AO² = 144
AO = 12
So, AC = 24 cm
BD = 10 cm (given)

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S5. Ans.(a)
Sol. radios = 10.5 cm

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S6. Ans.(b)
Sol. Product of two whole no. = HCF × LCM
1500 = 10 × LCM
LCM = 150

S7. Ans.(b)
Sol. 24.424 + 5.656 + 1.131 + 0.089 = x

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S8. Ans.(d)

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S9. Ans.(b)

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S10. Ans.(a)

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