Q2. Two forces are applied on a rubber ball kept at rest. At the beginning the forces are balanced. After sometimes the forces became unbalanced. Which of the following is true?
(a) Shape of ball will change
(b) Speed will be imparted in the ball
(c) Firstly the shape will change then speed will be imparted
(d) Firstly speed will be imparted then shape of the ball will start changing
Q3. Which of the following is not a non-contact force?
(a) Magnetic force
(b) Gravitational force
(c) Both (a) and (b)
(d) None of the above
Q4. Walking on ground, swimming, firing of a gun, all the activities are examples of
(a) Newton’s first law of motion
(b) Newton’s second law of motion
(c) Newton’s third law of motion
(d) None of the above
Q5. While going for a long drive, Akhil noted the reading on the odometer after every hour. The reading noted by him is given in the table below.
Time Odometer reading (km)
11 : 00 am 7856
12 : 00 pm 7876
1 : 00 pm 7889
2 : 00 pm 7955
What is the average speed of Akhil’s total journey?
(a) 40 km/hr
(b) 25 km/hr
(c) 33 km/hr
(d) 44 km/hr
Q6. Rocket works on the principle of conservation of
(a) mass
(b) energy
(c) momentum
(d) charge
Q7. Which of the following statement(s) is/are true?
I. Circular motion is a periodic motion.
II. A satellite has a uniform circular motion always.
(a) I is true
(b) II is true
(c) Both I and II are true
(d) Neither I nor II is true
Q8. In satellites, centripetal force is used to balance other force. Which force is that?
(a) Electrostatic force
(b) Frictional force
(c) Gravitational force
(d) Both (b) and (c)
Q9. Which of the following is not an application of centrifugal force?
(a) Separation of cream from milk
(b) Outer push felt on a merry-go-round
(c) Walking on ground
(d) None of the above
Q10. 100 N force is applied perpendicularly on the surface of 10 cm², the pressure on that surface will be
(a) 1 × 10⁵ N/m²
(b) 10 × 10⁵ N/m²
(c) 1 × 10⁻⁵ N/m²
(d) 10⁶ N/m²
Solutions
S1. Ans.(c)
Sol. Acceleration will be minimum when force will minimum.
So, net minimum force,
F = 25 N – 16 N = 9 N
Now, F = ma
⇒ 9 = 10 × a
⇒ a = 9 m/s²
S2. Ans.(c)
Sol.
Sol.
S4. Ans.(c)
Sol.
S5. Ans.(c)
Sol. Average speed = (Total distance covered)/(Total time taken)
Here total distance = 7955 – 7856 = 99 km
Time taken = 3 h
So, average speed = 99/3 = 33 km/hr
S6. Ans.(c)
Sol.
S7. Ans.(c)
Sol.
S8. Ans.(c)
Sol.
S9. Ans.(c)
Sol.