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# Reasoning Questions For DSSSB ,KVS Exam: 6th sept. 2018 The reasoning is the most scoring section in any competitive exam. It also develops or nourishes our critical thinking skills as compared to other subjects. In DSSSB,KVS Exam, As a student to score well in this part, you have to start your preparation now because there is negative marking as well. The more you have prepared, the better you score.

Q1. 1, 6, 15, ?, 45, 66, 91
(a) 25
(b) 26
(c) 27
(d) 28

Q2. 2, 5, 9, 19, 37, ?
(a) 73
(b) 75
(c) 76
(d) 78

Q3. 4, 8, 28, 80, 244, ?
(a) 278
(b) 428
(c) 628
(d) 728

Q4. 10000, 11000, 9900, 10890, 9801, ?
(a) 10241
(b) 10423
(c) 10781
(d) 10929

Q5. 0, 6, 24, 60, 120, 210, ?
(a) 240
(b) 290
(c) 336
(d) 504

Q6. 1, 4, 27, 16, ?, 36, 343
(a) 25
(b) 87
(c) 120
(d) 125

Q7. 4, 6, 12, 14, 28, 30, ?
(a) 32
(b) 60
(c) 62
(d) 64

Q8. 1, 3, 3, 6, 7, 9, ?, 12, 21
(a) 10
(b) 11
(c) 12
(d) 13

Q9. Which fraction comes next in the sequence 1/2,3/4,5/8,7/16,?
(a) 9/32
(b) 10/17
(c) 11/34
(d) 12/35

Q10. Find the missing term is the series : 3, 20, 63, 144, 275, ?
(a) 354
(b) 468
(c) 548
(d) 554

Solutions

S1. Ans.(d)
Sol. Clearly, the given sequence follows the pattern:
+5, +9, +13, +17, +21, +25, ……
Thus, 1 + 5 = 6, 6 + 9 = 15, ……
So, missing term = 15 + 13 = 28.

S2. Ans.(b)
Sol. Clearly, we have: 2 × 2 + 1 = 5, 5 × 2 – 1 = 9, 9 × 2 + 1 = 19, 19 × 2 – 1 = 37, ……
So, missing term = 37 × 2 + 1 = 75.

S3. Ans.(d)
Sol. The terms of the given series are:

So, missing term = 3⁶ – 1 = 729 – 1 = 728.

S4. Ans.(c)
Sol. Clearly, alternately we add and subtract 10% of a term to obtain the next term of the series.
Thus, 10000 + (10% of 10000) = 11000; 11000 – (10% of 11000) = 9900,
9900 + (10% of 9900) = 10890, 10890 – (10% of 10890)  = 9801.
So, missing term = 9801 + (10% of 9801) = 9801 + 980 = 10781.

S5. Ans.(c)
Sol. Clearly, the given series is: 1³ – 1, 2³ – 2, 3³ – 3, 4³ – 4, 5³ – 5, 6³ – 6.
∴ Missing term = 7³ – 7 = 343 – 7 = 336.

S6. Ans.(d)
Sol. Clearly, the given series consists of cubes of odd numbers and squares of even numbers, i.e., 1³, 2², 3³, 4², ……
So, missing term = 5³ = 125.

S7. Ans.(b)
Sol. The given sequence is a combination of two series:
I. 4, 12, 28, ? and II. 6, 14, 30, ……
Now, the pattern followed in each of the above two series is: +8, +16, +32, ……
So, missing number = (28 + 32) = 60.
Hence, the number is (b).

S8. Ans.(d)
Sol. Clearly, the given sequence is a combination of two series:
I. 1, 3, 7, ?, 21 and II. 3, 6, 9, 12
The pattern followed in I is +2, +4, …… and the pattern followed in II is +3.
So, missing number = 7 + 6 = 13.

S9. Ans.(a)
Sol. Clearly, the numerators of the fractions in the given sequence form the series 1, 3, 5, 7, in which each term is obtained by adding 2 to the previous term.
The denominators of the fractions from the series 2, 4, 8, 16, i.e., 2^1, 2², 2³, 2⁴.
So, the numerator of the next fraction will be (7 + 2) i.e. 9 and the denominator will be 2⁵ i.e. 32.
Thus, the next term is 9/32. Hence, the answer is (a). Join India's largest learning destination

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