**Q1. When the numerator of a fraction is increased by 4, the fraction increases by 2/3. What is the denominator of the fraction?**

**(a) 6**

(b) 7

(c) 8

(d) None of these

**Sol.**

**Let the fraction be x/y**

**According to condition**

**(x+4)/y=x/y+2/3**

**⇒x/y+4/y=x/y+2/3**

**⇒4/y=2/3⇒y=6**

**Q2. A pencil costs two and a half rupees. Amit buys one and a half dozen pencils and gives a 100 rupee note to the shopkeeper. The money he will get back is**

(a) Rs. 30

**(b) Rs. 55**

(c) Rs. 45

(d) Rs. 65

**Sol.**

**Cost of 1 pencil = Rs. 2.50**

**Amit bought one and a half dozen**

**= 12 + 6 = 18 pencils**

**The money he will get back**

**=100-(18×2.50)=100-45.00=Rs.55**

**Q3. A shop has 239 toys. Seventy more toys were brought in then 152 of them were sold. The number of toys left was**

**(a) 239 + 70 – 152**

(b) 239 – 70 – 152

(c) 239 + 70 + 152

(d) 239 – 70 + 152

**Sol.**

**Total number of toys = 239**

**Since, seventy more toys were brought in**

**∴ Total number of toys = 239 + 70**

**Now, 152 toys were sold**

**∴ Left toys = 239 + 70 – 152**

**Q4. The difference of 5671 and the number obtained on reversing its digits is**

(a) 7436

**(b) 3906**

(c) 4906

(d) 3916

**Sol.**

**Given number = 5671**

**After reversing its digits = 1765**

**∴ Difference = 5671 – 1765 = 3906**

**Q5. In the following, which is the greatest number?**

**(a) [(2+2)^2 ]^2**

(b) (2+2+2)^2

(c) 〖(4)〗^2

(d) 〖(2×2×2)〗^2

**Sol.**

**(4)^2=16**

**〖(2×2×2)〗^2=8^2=64**

**[(2+2)^2 ]^2=[〖(4)〗^2 ]^2=〖16〗^2=256**

**〖(2+2+2)〗^2=6^2=36**

**∴ Required number = [(2+2)^2 ]^2**

**Q6. A chocolate has 12 equal pieces. Manju gave one-fourth of it to Anju, one-third of it to Sujatha and one-sixth of it to Fiza. The number of pieces of chocolate left with Manju is**

(a) 4

(b) 1

(c) 2

**(d) 3**

**Sol.**

**Anju had =1/4×12=3 pieces**

**Sujatha had = 1/3×12=4 pieces**

**Fiza had = 1/6×12=2 pieces**

**Total pieces = 3 + 4 + 2 = 9 pieces**

**Choclate left with Manju = 12 – 9 = 3 pieces**

**Q7. What should be added to the product 140×101 to get 14414?**

(a) 364

(b) 264

**(c) 274**

(d) 278

**Sol.**

**Product of 140×101=14140**

**Difference = 14414-14140=274**

**274 is added to the product to get 14414.**

**Q8. What should be added to the product 103×301 to get 31103?**

(a) 301

(b) 103

(c) 110

**(d) 100**

**Sol.**

**Product of 103×301=31003**

**Now, 100 is to be added to get 31103.**

**Q9. Number of common factors of 12 and 16 is ____.**

**(a) 2**

(b) 3

(c) 4

(d) 5

**Sol.**

**Factors of 12 are = 2×2×3**

**Factors of 16 are = 2×2×2×2**

**Common factors of 12 and 16 are 2×2**

**Number of common factors of 12 and 16 are 2.**

**Q10. In a hockey match between School A and School B, School A scored 11 goals and School B scored 3 goals. What fraction of the total goals did School A score?**

(a) 3/14

(b) 8/11

**(c) 11/14**

(d) 11/3

**Sol.**

**Total goals = School A’s goals + School B’s goals = 11 + 3 = 14**