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# Maths Quiz for KVS/NVS & CTET Exams Q1. A train passes a platform 60 metres long in 30 seconds and a man standing on the platform in 15 seconds. The speed of the train is:
(a) 12.4 km/h
(b) 14.4 km/h
(c) 18.4 km/h
(d) 21.6 km/h

Q2. A train 300 metres long is running at a speed of 25 metre per second. It will cross a bridge of 200 metres in
(a) 5 seconds
(b) 10 seconds
(c) 20 seconds
(d) 25 seconds

Q3. A train 800 metres long is running at the speed of 78 km/hr. If it crosses a tunnel in 1 minutes, then the length of the tunnel (in metres) is:
(a) 7720
(b) 500
(c) 1300
(d) 13

Q4. A train is moving at a speed of 132 km/hour. If the length of the train is 110 metres, how long will it take to cross a railway platform of 165 metres long?
(a) 5 seconds
(b) 7.5 seconds
(c) 10 seconds
(d) 15 seconds

Q5. A truck covers a distance of 550 metres in 1 minute whereas a bus covers a distance of 33 kms in 45 minutes. The ratio of their speed is
(a) 4 : 3
(b) 3 : 5
(c) 3 : 4
(d) 50 : 3

Q6. A moving train crosses a man standing on a platform and a bridge 300 metres long in 10 seconds and 25 seconds respectively. What will be the time taken by the train to cross a platform 200 metres long?
(a) 16 2/3 seconds
(b) 18 seconds
(c) 20 seconds
(d) 22 seconds

Q7. The speed 3 1/3 m/sec when expressed in km/hour becomes
(a) 8
(b) 9
(c) 10
(d) 12

Q8. Two trains, A and B, start from stations X and Y towards each other, they take 4 hours 48 minutes and 3 hours 20 minutes to reach Y and X respectively. After they meet, if train A is moving at 45 km/hr, then the speed of the train B is
(a) 60 km/hr
(b) 64.8 km/hr
(c) 54 km/hr
(d) 37.5 km/hr

Q9. A man covers (9/20 )by bus and the remaining 10 km on foot. His total journey (in km) is
(a) 15.6
(b) 24
(c) 18.18
(d) 12.8

Q10. A is twice as fast as B and B is thrice as fact as C is. The journey covered by C in 1 1/2 hours will be covered by A in
(a) 15 minutes
(b) 2 minutes
(c) 30 minutes
(d) 1 hour
Solutions

S1. Ans.(b)
Sol. (l+60)/30=l/15
l + 60 = 2l
l = 60
Speed =(60/15)×(18/5)
= 14.4 km/h

S2. Ans.(c)
Sol. 500 = 25 × t
t = 20 sec

S3. Ans.(b)
Sol. (800+l)=78×(5/18)×60
800 + l = 1300
l = 500

S4. Ans.(b)
Sol. (110+165)=132×(5/18)×t
275=(660/18)×t
t = 7.5 seconds

S5. Ans.(c)
Sol. T : B =(550/60) ∶ (33 ×1000)/(45 ×60)
55 × 45 : 33 × 100
3 : 4

S6. Ans.(c)
Sol. (300 + l)/25 = (l/10)
25l = 3000 + 10l
15l = 3000
l = 200
Speed=200/10 = 20 m/s
=(200+200)/20
= 20 sec

S7. Ans.(d)
Sol. (10/3)×(18/5) = 12 km/h

S9. Ans.(c)

Sol. Total distance = D
(11D/20)=10
11D = 200
D=(200/11)
D = 18.18