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# Maths Quiz for KVS/NVS & CTET Exams Q1. A sum of Rs. 4000 is lent for 5 years at the rate of 15% per annum. Find the interest.
(a) 3000
(b) 2000
(c) 1000
(d) None of these

Q2. A sum of money becomes 6 times in 20 years at S.I. find the rate of interest.
(a) 20%
(b) 15%
(c) 16%
(d) 25%

Q3. In what time does a sum of money become four times at the simple interest rate of 10% per annum?
(a) 30 years
(b) 25 years
(c) 35 years
(d) 40 years

Q4. Ashok borrowed some money at the rate of 6% per annum for the first two years, at the rate of 9% per annum for the next three years and at the rate of 14% per annum for the period beyond five years. If he pays a total interest of 11400 at the end of 9 years. How much money did he borrow?
(a) 16000
(b) 14000
(c) 18000
(d) 12000

Q5. What principal will amount to 560 in 3 years at 4 percent per annum simple interest?
(a) 540
(b) 500
(c) 550
(d) 560

Q6. A man wants to invest Rs. 3900 in account of his two sons who are 14 years and 16 years old in such a way that they will get equal amount at the time of attaining the age 18 years. If rate of interest per annum is 10% then find the amount he deposit in account of his younger son?
(a) 1500
(b) 1200
(c) 1900
(d) 1800

Q7. A certain sum of money amounts of 5000 in five years at 10% per annum. In how many years will it amount to 6000 at the same rate?
(a) 8 years
(b) 6 years
(c) 10 years
(d) 9 years

Q8. A man had 2000, part of which he lent at 5% and the rest at 4% the whole annual interest was 92. How much did he lent at 5%
(a) 1200
(b) 800
(c) 700
(d) 1300

Q9. A sum of money becomes five times at the simple interest rate of 8% per annum. At what % will it become seven fold at same time.
(a) 6%
(b) 10%
(c) 12%
(d) 14%

Q10. If Rahim deposited the same amount of Rs. x in a bank at the beginning of successive 3 years and the bank pays compound interest at 5% per annum, then the amount at his credit at the end of 3rd year will be?
(a) 861x/400
(b) 1261x/400
(c) 21x/20
(d) 26481x/8000
Solutions

S1. Ans.(a)
Sol. P= 4000, T = 5 years, R = 15%
Total interest = (4000×15×5)/100
= 3000

S2. Ans.(d)
Sol. (5/1)×100=500%
R × T = 500%
20 × R = 500%
R = 25%

S3. Ans.(a)
Sol. (3/1)×100=300%
R × T = 300%
10% × T = 300%
T = 30 years

S7. Ans.(a)
Sol. (P × 5 × 10)/100 = 5000 – P  …(i)
(P × T × 10)/100 = 6000 – P  …(ii)
Solving (i) and (ii)
P = 10000/3
Putting it in (ii)
T = 8 years

S9. Ans.(c)
Sol.
(4/1)×100=400%
8%×T=400%
T = 50 years
(6/1)×100=600%
50 × R = 600%
R = 12%