Q1. In a question of division, if divisor is 51, quotient 16 and remainder 27, then the dividend will be
(a) 843
(b) 483
(c) 94
(d) 139
Sol.
As we know,
Dividend = Divisor × Quotient + Remainder
∴ Dividend = 51 × 16 + 27 = 816 + 27 = 843
Q2. In figure determine the value of y.
(a) 25°
(b) 35°
(c) 15°
(d) 40°
Sol.
In the figure, ∠COF=∠EOD=5y
Now, 5y + 5y + 2y = 180° [linear pair property]
12y = 180° ⇒ y = 15°
Q3. Three balls start ringing together at 8: 30 am. If they ring after 4, 5 and 6 min respectively each time, the next time they will ring together at
(a) 8 : 45 am
(b) 9: 30 am
(c) 9 : 45 am
(d) 10 : 15 am
Sol.
The LCM of 4, 5 and 6 = 60
Hence, after 60 min i.e. after 1 h
They will ring together i.e. at 9 : 30 am
Q4. The next number in the series 2, 5, 8, 11… is
(a) 12
(b) 10
(c) 14
(d) 15
Sol.
The pattern of series is
Q5. If the circumference of a circle is 88 cm, then the area of the circle is
(a) 48 π
(b) 64 π
(c) 92 π
(d) 196 π
Sol.
2πr=88 cm ⇒2×22/7×r=88⇒r=(88 × 7 )/(22 × 2)=14 cm
∴ Area of circle =πr^2=π(14)^2=196 π
Q6. Out of a total of 250 marks, a student got 30% marks and failed by 25 marks. The marks necessary for passing is
(a) 50
(b) 75
(c) 100
(d) 125
Sol.
∴ Total marks = 250
Student got = 30% i.e. 250×30/100= 75 marks
Failed by = 25 marks
∴ Pass marks = 75 + 25 = 100 marks
Q7. The average of four numbers is 30. If the sum of first three numbers is 85, the fourth number is
(a) 30
(b) 35
(c) 45
(d) 55
Sol.
∴ The average of four numbers = 30
∴ Total of our numbers = 30 × 4 = 120
Sum of first three numbers = 85
∴ Fourth number = (120 – 85) = 35
Q8. A boy gets Rs. 20 per month and spends 50% of it. How much does he save in one year?
(a) Rs. 100
(b) Rs. 50
(c) Rs. 120
(d) Rs. 40
Sol.
Monthly saving amount by the boy = Rs. 20 ×50/100 = Rs. 10
∴ Annually saving amount = Rs. 10 × 12 = Rs. 120
Q9. The value of 5-(2 1/2-3/4)+(3 1/2-1 1/4) is
(a) 4 1/2
(b) 5 1/2
(c) 5 1/4
(d) 3 1/2
Sol.
5-[5/2-3/4]+[7/2-5/4]=5-[(10-3)/4]+[(14-5)/4]=5-7/4+9/4
=(20-7+9)/4=22/4=11/2=5 1/2
Q10. A person borrowed a sum of Rs.20000 for two years on simple interest. He had to repay Rs. 24800 including interest after two years. The rate of interest per annum was
(a) 48%
(b) 24%
(c) 12%
(d) 6%
Sol.
Amount = Rs. 24800
Principal = Rs. 20000
∴ SI = (Amount – Principal) = 24800 – 20000 = Rs. 4800
Rate of interest = (SI × 100)/(P × T)=(4800 ×100)/(20000 ×2)=12%
