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# Maths Questions for CTET Exam 2017

Q1. The selling price of 40 articles is the same as the cost price of 50 articles. Find the gain per cent.
(a) 20%
(b) 15%
(c) 25%
(d) 35%
Q2. A lady bought 400 oranges at the selling price of 320 oranges. His gain percentage is
(a) 15
(b) 25
(c) 30
(d) 35
Q3. The difference between the selling price and cost price of an article is Rs. 210. If the profit per cent is 25, then the selling price of the article is
(a) Rs. 1150
(b) Rs. 1050
(c) Rs. 1250
(d) Rs. 1350
Q4. If the selling price is 85% of the cost price, what is the loss per cent?
(a) 24
(b) 20
(c) 15
(d) 16
Q5. A retailer buys a book for Rs. 250. His overhead expenses are Rs. 10. He sells the book for Rs. 325. The profit per cent of the retailer is
(a) 25
(b) 28 (2/3)
(c) 24
(d) 30 (1/6)
Q6. A lady sold an article at a loss of 20%. If he has sold that article for Rs. 12 more he would have gained 20%. Find the cost price of that article
(a) Rs. 50
(b) Rs. 40
(c) Rs. 30
(d) Rs. 25
Q7. If an article sold at a gain of 9% interest is being sold at a loss of 9%. It gets Rs. 9 more. What is the cost price of the article?
(a) Rs. 105
(b) Rs. 100
(c) Rs. 50
(d) Rs. 115

Q8. Aman sells a wall clock at a profit of 10%. If he had bought the wall clock at 5% less and sold it for Rs. 80 more, he would have gained 20%. The cost price of the wall clock is
(a) Rs. 2350
(b) Rs. 2520
(c) Rs. 2000
(d) Rs. 3000
Q9. A shopkeeper sold half of his cloth at 30% loss, half of remaining at 20% profit and the rest was sold at the cost price. In the total transaction his gain or loss will be
(a) 15% gain
(b) 15% loss
(c) 10% gain
(d) 10% loss
Q10. A dealer sold two bicycles for Rs. 8400 each. On one he gained 25% and on the other he lost 25%. The dealer’s loss or gain in the transaction is
(a) 6.25% loss
(b) 1.25% gain
(c) 6.25% profit
(d) no profit no loss
Solutions

S3. Ans.(b)
Sol. P% = 25
25% = 1/4
C.P. S.P.
4       5
1—–210
S.P. = 210 × 5
= 1050
S4. Ans.(c)
Sol. C.P. = 100
S.P. = 85
L% =(15/100)×100
= 15%
S5. Ans.(a)
Sol. Total C.P. = 250 + 10
= 260
S.P. = 325
P = 65
P% =(65/260)×100
= 25%
S6. Ans.(c)
Sol. (40/12)= (100/y)
y = 30
S7. Ans.(c)
Sol. (18/9) = (100/y)
y = 50
S10. Ans.(a)
Sol. Loss% =-(x/10)^2
-(625/100) = -6.25%