Home   »   Maths Quiz for KVS/NVS & CTET...

# Maths Quiz for KVS/NVS & CTET Exams Q1. If 3/4 of a number is 7 more than 1/6 of the number then 5/3 of the number is;
(a) 12
(b) 18
(c) 15
(d) 20

Q2. If x = 1/(√(2 + 1) then (x + 1) equal to
(a) √2+1
(b) √2-1
(c) √2
(d) 2

Q3.  If a * b = a + b + a/b, then the value of 12 * 4 is:
(a) 20
(b) 21
(c) 48
(d) 19

Q4. Find the maximum number of trees which can be planted 20 m apart, on two sides of a straight road 1760 m long
(a) 180
(b) 178
(c) 174
(d) 176

Q5. Mohan gets 3 marks for each correct sum and loses 2 marks for each wrong sum. He attempts 30 sums and obtains 40 marks. The number of sums solved correctly is:
(a) 15
(b) 20
(c) 25
(d) 10

Q6. Two trains 108 m and 112 m in length are running towards each other on the parallel lines at a speed of 45 km/hr and 54 km/hr respectively. To cross each other after they meet, it will take
(a) 12 sec
(b) 9 sec
(c) 8 sec
(d) 10 sec

Q7. Two trains 150 m and 120 m long respectively moving from opposite directions cross each other in 10 seconds. If the speed of the second train is 43.2 km/hr, then the speed of the first train is
(a) 54 km/hr
(b) 50 km/hr
(c) 52 km/hr
(d) 51 km/hr

Q8. A bus moving at a speed of 45 km/hr overtakes a truck 150 m ahead going in the same direction in 30 seconds. The speed of the truck is
(a) 27 km/hr
(b) 24 km/hr
(c) 25 km/hr
(d) 28 km/hr

Q9. A passenger train 150 m long is travelling with a speed of 36 km/hr. If a man is cycling in the direction of train at 9 km/hr., the time taken by the train to pass the man is
(a) 10 sec
(b) 15 sec
(c) 18 sec
(d) 20 sec

Q10. The speed of two trains are in the ratio 6 : 7. If the second train runs 364 km in 4 hours, then the speed of first train is
(a) 60 km/hr
(b) 72 km/hr
(c) 78 km/hr
(d) 84 km/hr

Solutions

S1. Ans.(d)
Sol. Let the number be x
⇒ According to the question,
⇒ 3x/4-x/6 = 7
⇒ (9x – 2x)/12 = 7
⇒ 7x = 7 × 12
⇒ x = 12
⇒ Then 5/3 of the number will be
= (x ×5)/3 ⇒ (12 × 5)/3 = 20

S3. Ans.(d)

Sol. 12 * 4 = 12 + 4 + 12/4
= 12 + 4 +3 = 19

S6. Ans.(c)
Sol. Time taken by them to cross each other
=(l1+l2)/(Relative speed in opposite direction)
Time = (108 + 112)/((45 + 54) × 5/18)=(220 × 18)/(99 × 5)
Time = 8 second