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# Maths Questions for CTET Exam 2017

Q1. The sum of the present ages of P and Q is 120 years. Also 15 years ago, the ratio of the ages of P and Q was 6 : 3. Find the present age of P.
(a) 45 years
(b) 75 years
(c) 35 years
(d) 54 years
Q2. The total ages of M, N and O at present is 90 years. Fifteen years ago, the ratio of their ages was 2 : 3 : 4. Then the present age of O is:
(a) 30 years
(b) 35 years
(c) 40 years
(d) 45 years
Q3. The ratio of P and Q ages is 5 : 4. The product of their ages is 720 years. Then P’s present age is.
(a) 30 years
(b) 32 years
(c) 35 years
(d) 40 years
Q4. The age of Jasmine is thrice the age of her younger sister. The product of their ages is 300 years. Then the Jasmine’s present age is.
(a) 25 years
(b) 35 years
(c) 40 years
(d) 30 years
Q5. The product of the ages of Ajay and Ananya is 240. If twice the age of Ananya is more than Ajay’s age by 4 years, what is Ananya’s age?
(a) 12 years
(b) 18 years
(c) 20 years
(d) 24 years
Q6. The ratio of the ages of A and B, 12 years ago was 2 : 3. If the ratio of their present ages is 5 : 6, what will be the total of their present ages.
(a) 40 years
(b) 42 years
(c) 44 years
(d) 46 years
Q7. The ratio of the ages of P and Q at present is 4 : 3 : 10 years earlier, the ratio was 3 : 2. Find the present ages of P and Q.
(a) 40 yrs and 30 yrs
(b) 45 yrs and 55 yrs
(c) 58 yrs and 48 yrs
(d) 50 yrs and 60 yrs
Q8. Akhil is twice as old as Vineeta. Twelve years ago, Akhil was five times as old as Vineeta. Find the present age of Akhil.
(a) 30 years
(b) 24 years
(c) 20 years
(d) 16 years
Q9. Four years ago, the age of the mother was 8 times the age of her daughter. At present the mother’s age is 6 times that of her daughter. Find the present age of daughter.
(a) 14 years
(b) 17 years
(c) 19 years
(d) 21 years

Q10. The ratio of the present ages of A and B is 5 : 8. After four years, the ratio between their ages will be 2 : 3. What is B’s age at present.
(a) 36years
(b) 20years
(c) 24years
(d) 32years
Solutions
S3. Ans.(a)
Sol. P      Q
5x    4x
20x^2=720
x^2=36
x = 6
P = 5 × 6
= 30
S4. Ans.(d)
Sol. smaller sister = x
Jasmine’s age = 3x
3x^2=300
x^2=100
x=10
Jasmine’s age = 3 × 10 = 30
S5. Ans.(a)
Sol. Ananya = x
Ajay = 2x – 4
x(2x – 4) = 240
2x^2-4x=240
x^2-2x-120=0
x^2-12x+10x-120=0
x(x-12)+10(x-12)=0
x = 12
S6. Ans.(c)
Sol. A = 2x
B = 3x
(2x+12)/(3x+12)=5/6
12x+72=15x+60
3x=12
x = 4
Total = 11x
= 11 × 4
= 44 years
S7. Ans.(a)
Sol. P : Q
4 : 3
(3x+10)/(2x+10)=4/3
9x + 30 = 8x + 40
x = 10
P     Q
40, 30
S8. Ans.(d)
Sol. Akhil = 2x
Vineeta = x
(2x – 12) = 5(x – 12)
2x – 12 = 5x – 60
3x = 48
x = 16
Akhil = 2 × 16
= 32 years
S9. Ans.(a)
Sol. Daughter = x
Mother = 8x
6(x + 4) = (8x + 4)
6x + 24 = 8x + 4
2x = 20
x = 10
Daughter = 10 + 4
= 14 years
S10. Ans.(d)
Sol. A = 5x
B = 8x
(5x + 4)/(8x + 4)=2/3
15x + 12 = 16x + 8
x = 4
B = 8 × 4 = 32