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# Reasoning Quiz For KVS 2016 Exams

Q1. 2A11, 4D13, 12G17, ?

(a) 36I19
(b) 36J21
(c) 48J21
(d) 48J23

Directions(2-3): In each of the following letters series, some of the letters are missing which are given in that order as one of the alternatives below it. Choose the correct alternative.

Q2. ab _ bcbca _ _ c _ bab
(a) acbc
(b) ccaa
(c) abcc
(d) baaa

Q3. aa _ _ aba _ bca _ aab _ a _
(a) bbccab
(b) bbabcb
(c) bcabcb
(d) cbabac

Directions(4-5): There is a certain relation between two given words on one side of : : and one word is given on another side of : : while another word is to be found from the given alternatives, having the same relation with this word as the given pair has. Select the best alternatives.

Q4. Cattle : Herd : : Sheep : ?
(a) Flock
(b) Swarm
(c) Shoal
(d) Mob

Q5. Bank : Money : : Transport : ?
(a) Traffic
(c) Goods
(d) Speed

Directions (6-7): In each of the following questions, choose that set of numbers from the four alternative sets, that is similar to the given set.

Q6. Given set: (9, 15, 21)
(a) (10, 14, 16)
(b) (7, 21, 28)
(c) (5, 10, 25)
(d) (4, 8, 12)

Q7. Given set: (18, 8, 2)
(a) (3, 7, 1)
(b) (11, 12, 10)
(c) (17, 9, 3)
(d) (24, 22, 4)

Q8. If O = 16, FOR = 42, then what is FRONT equal to?
(a) 61
(b) 65
(c) 73
(d) 78

9.Buffoon : Drama : : Joker : ?
(a) Puppetry
(b) Playing cards
(c) Circus
(d) Laughing
10 .Safe : Secure : : Protect : ?
(a) Guard
(b) Lock
(c) Sure
(d) Conserve

Solutions:

S1.Ans.(d)
Sol.

S2.Ans.(b)
Sol. The series is abcbc/bcaca/cabab.
Thus, the series consist of three sequences. The first sequence begins with a, the second with b and the third with c. Each sequence consists of a letter followed by the pair of other two letters repeated twice.

S3.Ans.(c)
Sol. The series is aabcab/aabcab/aabcab.

S4.Ans.(a)
Sol. Herd is a group of cattle. Similarly, flock is a collection of sheep.

S5.Ans.(c)
Sol. Transaction of second is done through the first.

S6.Ans.(d)
Sol. In the given set, (1st number + 3rd number )/2= 2nd number.
So, (4 + 12 )/2=8

S7.Ans.(d)
Sol. Given set consists of even numbers only whose H.C.F. is 2.

S8.Ans.(d)
Sol. We have : A = 2, B = 3, ….., Z = 27. Then,
FOR = F + O + R = 7 + 16 + 19 = 42.
FRONT = F + R + O + N + T = 7 + 19 + 16 + 15 + 21 = 78.

S9.S9. Ans.(c)

Sol. Joker performs in circus.

S10.S10. Ans.(a)

Sol.