**Q1. Sum of cost price of two watches is Rs 3360. One watch is sold at a profit of 12% and other at a loss of 12%. Due to this transaction, there is neither profit nor loss. Find the cost price of each watch.**

(a) Rs 1680, Rs 1680

(b) Rs 1280, Rs 1280

(c) Rs 1000, Rs 1000

(d) Rs 2100, Rs 2160

**Q2. A seller buys 50 kg oranges for Rs 525 and gains a profit equal to the cost price of 10 kg of oranges. Find the selling price per kg of oranges (Rs/kg).**

(a) 12.60

(b) 11.60

(c) 10.20

(d) 12

**Q3. Find a number, one-seventh of which exceeds its eleventh part by 100.**

(a) 1925

(b) 1825

(c) 1540

(d) 1340

**Q4. 6 bells commence tolling together and toll of intervals are 2, 4, 6, 8, 10 and 12 s, respectively. In one hour, how many times do they toll together?**

(a) 16

(b) 32

(c) 21

(d) 31

**Q5. A certain type of board is sold in lengths of multiples of 2 ft. the shortest board sold is 6 ft and the longest is 24 ft. A builder needs a large quantity of these types of board in 5 1/2 ft lengths. Find the length of be ordered for which waste is minimum.**

(a) 24 ft

(b) 26 ft

(c) 22 ft

(d) 52 ft

**Q6. Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit’s present salary?**

(a) Rs. 20,000

(b) Rs, 30,000

(c) Rs, 38,000

(d) Rs.45, 000

**Q7. The ratio between the rates of walking of A and B is 3:4 . If the time taken by B to cover a certain is 48 minutes, the time taken (in minutes) by A to cover that distance is :**

(a) 36

(b) 64

(c) 21(5/7)

(d) 27(3/7)

**Q8. A fruit seller buys mangoes at the rate of 15 for 12 and sells them at the rate of 15 per dozen. Find his gain percentage.**

(a) 25.65%

(b) 32.25%

(c) 51.35%

(d) 56.25%

**Q9. Summer started cycling along the boundaries of a square field from corner point A. After half an hour he reached the corner point C, diagonally opposite of A. If his speed was 8 kmph, what is the area of the field in sq. km?**

(a) 64

(b) 8

(c) 4

(d) None of these

**Q10. A man riding a cycle at 12 km/hr can reach a village in 4(1/2) hours. If he is delayed by 1(1/2 ) hours at the start, then in order to reach his destination in time, he should ride with a speed of:**

(a) 15 km/hr

(b) 16 km/hr

(c) 18 km/hr

(d) 20 km/hr

**Solutions**

S1. Ans.(a)

Sol.

On one watch, he earns 12% profit and on the other one 12% loss. There is, finally, no profit no loss.

Hence CPs of both the watches should be same such that their summation = Rs 3360.

Hence CP/watch = (Rs.3360)/2 = Rs. 1680

Hence option (a) is the answer.

S2. Ans.(a)

Sol.

Assume SP/kg = Rs x/kg.

CP/kg =(Rs.525)/50 = Rs. 10.5/kg

Total SP – Total CP = profit ⇒ 50x – Rs. 525 = 10 × Rs. 10.5 = Rs. 105

Or, 50x = Rs. 105 + Rs. 525 = Rs. 630

Hence x =(Rs.630)/50 = Rs. 12.6/kg

S3. Ans.(a)

Sol.

Let the number be x.

x/7- x/11 = 100

(11x-7x)/ (11 x 7)=100

4x = 77 x 100

x = 1925

S4. Ans.(d)

Sol.

LCM of 2, 4, 6, 8, 10, 12 = (2 × 2 × 3 × 2 × 5) = 120

∴ After every 2 min they toll together

∴ Number of times they toll together in one hour

=(60/2+1) times = 31 times

S5. Ans.(c)

Sol.

LCM of (2 and 5 1/2) = LCM of (2 and 11/2)

Required answer = (LCM of 2 and 11)/(HCF of 1 and 2)=22/1 = 22 ft

S6. Ans.(c)

Sol.

Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.

Then, (2x + 4000)/ (3x + 4000)= 40/57

57(2x + 4000) = 40(3x + 4000)

6x = 68,000

3x = 34,000

Sumit’s present salary = (3x + 4000) = Rs. (34000+ 4000) = Rs. 38,000

S7. Ans.(b)

Sol.

Ratio of time taken = 1/3 : 1/4 = 4:3

If B takes 3 min ,A takes 4 min

If B takes 48 min ,A takes (4/3 × 48)min = 64 minutes

S8. Ans.(d)

Sol.

C.P. of one mango = 12/15 = 80 paise ; S.P. of one mango = 15/12=Rs 1.25

Gain = 45 paise , gain = 45/80 × 100 = 56.25 %

S9. Ans.(c)

Sol.

Distance covered in half an hour = 4 km.

2× side of the square = 4 km

side of square = 2 km

So Area of the field = 4 sq.km.

S10. Ans.(c)

Sol.

Distance = (Speed× Time)= (12× 9/12) km = 54 km

Now, distance = 54 km and time taken = 3 hrs.

so speed = distance/time = 54/3 = 18 km/hr.