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# Maths Quiz for KVS/NVS & CTET Exams Q1. If x * y = (x+3)^2  (y-1), then the value of 5 * 4 is
(a) 192
(b) 182
(c) 180
(d) 172

Q2. If 9√x=√12+√147, then x = ?
(a) 2
(b) 3
(c) 4
(d) 5

Q3. If X * Y = X^2+Y^2-XY then 11 * 13 is
(a) 117
(b) 147
(c) 290
(d) 433

Q5. If √(0.04×0.4×a) = 0.004 × 0.4 × √b, then the value of a/b is
(a) 16 × 10^(-3)
(b) 16 × 10^(-4)
(c) 16 × 10^(-5)
(d) 16 × 10^(-6)

Q6. A dealer wants to earn 20% profit on an article after offering 25% discount to the customer. If the cost price of an item is Rs. 400, then the mark price (label price) of the article would be
(a) 500
(b) 400
(c) 440
(d) 640

Q7. P, Q and R can do a piece of work in 10, 12 and 15 days respectively, they start working together but R leaves after working 3 days and Q, 4 days before the completion of work. In how many days the work was finished?
(a) 7 2/11 days
(b) 6 2/11 days
(c) 8 2/11 days
(d) 9 2/11 days

Q8. A does 4/5th of a work in 20 days. He then calls in B and they together finish the remaining work in 3 days. How long B alone would take to do the whole work?
(a) 47 1/2 days
(b) 36 1/2 days
(c) 37 1/2 days
(d) 39 1/2 days

Q9. In 1 minute 3/7 of a bucket is filled. The rest of the bucket can be filled in.
(a) 2 minutes
(b) 4/3 minutes
(c) 7/3 minutes
(d) None of these

Q10. Two pipes can fill a tank in 20 minutes and 30 minutes respectively. If both the pipes are opened simultaneously, then the tank will be filled in
(a) 10 minutes
(b) 12 minutes
(c) 15 minutes
(d) 25 minutes

Solutions

S1. Ans.(a)
Sol. x * y = (x+3)^2 (y-1)
5 * 4 = (5+3)^2 (4 – 1)
= 64 × 3 = 192

S2. Ans.(b)
Sol. 9√x=√12+√147
9√x=√(4×3)+√(49×3)
9√x=9√3
x = 3

S3. Ans.(b)
Sol. X * Y = X^2+Y^2-XY
11 * 13 = (11)^2+(13)^2-11×13
= 121 + 169 – 143 = 147

S7. Ans.(b)
Sol. Let the work be finished in x days.
(x/10)+((x-4)/12)+(3/15)=1
or, x = 6 2/11 days

S8. Ans.(c)
Sol. 4/5 work is done by A in 20 days.
Whole work is done by A in
= (20×5/4) = 25 days
1/5th work is done by (A + B) in 3 days.
Whole work is done by (A + B) in (3 × 5) days = 15 days.
B’s 1 day’s work = (1/15)-(1/25)=2/75
B alone can finish the work in = 75/2=37 1/2 days

S9. Ans.(b)
Sol. Part filled in 60 sec = 3/7
i.e full bucket filled in =140 sec
Remaining part = 1-(3/7)=4/7
Therefore, Remaining part filled in = 140 × 4/7
= 80 sec
=80/60 = 4/3 min

S10. Ans.(b)
Sol. Part filled by both pipes in 1 min
=(1/20)+(1/30)=5/60=1/12
Time taken to fill the tank = 12 minutes.