Q1. When 3488 is divided by 12 and 2478 is divided by 11, the difference between the remainders in both cases is
(a) 5
(b) 6
(c) 7
(d) 3
Sol.
When 3488 is divided by 12 gives remainder 8
When 2478 is divided by 11 gives remainder 3
Difference = 8 – 3 = 5.
Q2. A train leaves station P at 8:18 a.m. and reaches station Q at 10:28 p.m. on the same day. The time taken by the train to reach Q is
(a) 14 hours 10 minutes
(b) 14 hours 46 minutes
(c) 18 hours 46 minutes
(d) 13 hours 10 minutes
Sol.
Train leaves P at 8:18 a.m.
Train reaches Q at 10:28 p.m. or 22:28
Time taken = 22:28 – 8:18 = 14:10
Q3. 14 l 280 ml of orange juice and 18 l 830 ml of carrot juice were mixed together. This mixture was filled in 15 bottles each containing 1.5 l. How much mixture was left?
(a) 11 l 105 ml
(b) 9 l 610 ml
(c) 11 l 605 ml
(d) 10 l 610 ml
Sol.
14.280 l orange juice + 18.830 l Carrot juice = 33.110 l
Capacity of 15 bottle = 1.5×15=22.5 l
Mixture left = 33.110-22.5=10.610 l
Q4. One-fourth of a pizza was eaten by Renu. The rest was equally distributed among 12 children. What part of the pizza did each of these children get?
(a) 1/16
(b) 1/32
(c) 3/16
(d) 1/8
Sol.
Pizza remaining = 3/4
Pizza that single child get = 3/(4 × 12)=1/16
Q5. On dividing 110111 by 11, the sum of the quotient and the remainder is
(a) 11011
(b) 11001
(c) 10101
(d) 10011
Sol.
The remainder would be 1 and the quotient would come out is 10010 and their sum would be 10011.
Q6. A one-litre carton of juice is in the shape of a cuboid and has a square base of size 8 cm by 8 cm. The depth of juice in the carton, in centimeters, is closet to
(a) 20
(b) 22
(c) 16
(d) 18
Sol.
The area of base of cuboidal box = 8×8=64 〖cm〗^2 Therefore, the depth or
Height of the juice box is 1000/64
=15.625 cm ≈16 cm (∴1 l=1000 〖cm〗^3 )
Q7. The sum of place values of 5 in 6251,6521 and 5621 is
(a) 550
(b) 15
(c) 5550
(d) 5050
Sol.
Place value of 5 in 625 is 50
Place value of 5 in 6521 is 500
Place value 5 in 5621 is 5000
Therefore, the sum of place values = 50 + 500 + 5000 = 5550
Q8. A train leaves a station at 6:14 a.m. and reaches its destination after 13 hours 48 minutes. The time at the destination is
(a) 8:02 p.m.
(b) 8:12 p.m.
(c) 7:02 p.m.
(d) 7:12 p.m.
Sol.
After 13 hours, the time will be 7:14 and after 48 minutes the time will be 8:02.
Q9. Ravi has three dozen chocolates. He gave one-third of them to his neighbor, one-sixth to Rehana and one-fourth to his sister. How many chocolates are left with him?
(a) 9
(b) 10
(c) 6
(d) 8
Sol.
Total number of chocolates given to the neighbor
=1/3×(36)+1/6×(36)+1/4×(36)
(∴ 1 dozen = 12)
= 12 + 6 + 9 = 27
No. of chocolates left after distribution = 36 – 27 = 9
Q10. Perimeter of a square is 44 cm. The perimeter of a rectangle is equal to the perimeter of this square. The length of the rectangle is 5 cm more than the side of the square. The sum of are (〖in cm〗^2 ) of the square and the rectangle is
(a) 217
(b) 229
(c) 169
(d) 140
Sol.
Perimeter of square = 44 cm
⇒4× side of square = 44
∴ Side of square = 11 cm
∴ Length of rectangle = 11 + 5 = 16 cm
Given that
The perimeter of a rectangle = The perimeter of square.
⇒ 2 (length + breadth) = 44
⇒ 2 (16 + breadth) = 44
∴ Breadth = 6
Area of rectangle = 16×6=96 〖cm〗^2
Area of square = 〖(11)〗^2=121 〖cm〗^2
Sum of area of square and area of rectangle = 96 + 121 = 217 〖cm〗^2
