**Q1. When 3488 is divided by 12 and 2478 is divided by 11, the difference between the remainders in both cases is**

**(a) 5**

(b) 6

(c) 7

(d) 3

**Sol.**

**When 3488 is divided by 12 gives remainder 8**

**When 2478 is divided by 11 gives remainder 3**

**Difference = 8 – 3 = 5.**

**Q2. A train leaves station P at 8:18 a.m. and reaches station Q at 10:28 p.m. on the same day. The time taken by the train to reach Q is**

**(a) 14 hours 10 minutes**

(b) 14 hours 46 minutes

(c) 18 hours 46 minutes

(d) 13 hours 10 minutes

**Sol.**

**Train leaves P at 8:18 a.m.**

**Train reaches Q at 10:28 p.m. or 22:28**

**Time taken = 22:28 – 8:18 = 14:10**

**Q3. 14 l 280 ml of orange juice and 18 l 830 ml of carrot juice were mixed together. This mixture was filled in 15 bottles each containing 1.5 l. How much mixture was left?**

(a) 11 l 105 ml

(b) 9 l 610 ml

(c) 11 l 605 ml

**(d) 10 l 610 ml**

**Sol.**

**14.280 l orange juice + 18.830 l Carrot juice = 33.110 l**

**Capacity of 15 bottle = 1.5×15=22.5 l**

**Mixture left = 33.110-22.5=10.610 l**

**Q4. One-fourth of a pizza was eaten by Renu. The rest was equally distributed among 12 children. What part of the pizza did each of these children get?**

**(a) 1/16**

(b) 1/32

(c) 3/16

(d) 1/8

**Sol.**

**Pizza remaining = 3/4**

**Pizza that single child get = 3/(4 × 12)=1/16**

**Q5. On dividing 110111 by 11, the sum of the quotient and the remainder is**

(a) 11011

(b) 11001

(c) 10101

**(d) 10011**

**Sol.**

**The remainder would be 1 and the quotient would come out is 10010 and their sum would be 10011.**

**Q6. A one-litre carton of juice is in the shape of a cuboid and has a square base of size 8 cm by 8 cm. The depth of juice in the carton, in centimeters, is closet to**

(a) 20

(b) 22

**(c) 16**

(d) 18

**Sol.**

**The area of base of cuboidal box = 8×8=64 〖cm〗^2 Therefore, the depth or**

**Height of the juice box is 1000/64**

**=15.625 cm ≈16 cm (∴1 l=1000 〖cm〗^3 )**

**Q7. The sum of place values of 5 in 6251,6521 and 5621 is**

(a) 550

(b) 15

**(c) 5550**

(d) 5050

**Sol.**

**Place value of 5 in 625 is 50**

**Place value of 5 in 6521 is 500**

**Place value 5 in 5621 is 5000**

**Therefore, the sum of place values = 50 + 500 + 5000 = 5550**

**Q8. A train leaves a station at 6:14 a.m. and reaches its destination after 13 hours 48 minutes. The time at the destination is**

**(a) 8:02 p.m.**

(b) 8:12 p.m.

(c) 7:02 p.m.

(d) 7:12 p.m.

**Sol.**

**After 13 hours, the time will be 7:14 and after 48 minutes the time will be 8:02.**

**Q9. Ravi has three dozen chocolates. He gave one-third of them to his neighbor, one-sixth to Rehana and one-fourth to his sister. How many chocolates are left with him?**

**(a) 9**

(b) 10

(c) 6

(d) 8

**Sol.**

**Total number of chocolates given to the neighbor**

**=1/3×(36)+1/6×(36)+1/4×(36)**

**(∴ 1 dozen = 12)**

**= 12 + 6 + 9 = 27**

**No. of chocolates left after distribution = 36 – 27 = 9**

**Q10. Perimeter of a square is 44 cm. The perimeter of a rectangle is equal to the perimeter of this square. The length of the rectangle is 5 cm more than the side of the square. The sum of are (〖in cm〗^2 ) of the square and the rectangle is**

**(a) 217**

(b) 229

(c) 169

(d) 140

**Sol.**

**Perimeter of square = 44 cm**

**⇒4× side of square = 44**

**∴ Side of square = 11 cm**

**∴ Length of rectangle = 11 + 5 = 16 cm**

**Given that**

**The perimeter of a rectangle = The perimeter of square.**

**⇒ 2 (length + breadth) = 44**

**⇒ 2 (16 + breadth) = 44**

**∴ Breadth = 6**

**Area of rectangle = 16×6=96 〖cm〗^2**

**Area of square = 〖(11)〗^2=121 〖cm〗^2**

**Sum of area of square and area of rectangle = 96 + 121 = 217 〖cm〗^2**