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# Maths Quiz for KVS/NVS & CTET Exams Q1. Successive discounts of 10% and 30% are equivalent to a single discount of:
(a) 40%
(b) 35%
(c) 38%
(d) 37%

Q2. A trademan marks his good at 20% above the cost price. He allows his customers a discount of 8% on marked price. Find out his profit percent.
(a) 12%
(b) 10.4%
(c) 16%
(d) 20%

Q3. A discount of 2 1/2% is given to the customer on the marked price of an article. A man bought the article for Rs. 39. The marked price of the article is:
(a) Rs. 42
(b) Rs. 36.5
(c) Rs. 40
(d) Rs. 41.5

Q4. The marked price of a watch is Rs. 1000. A retailer buys it at Rs. 810 after getting two successive discounts of 10% and another rate which is eligible. What is the second discount rate?
(a) 15%
(b) 10%
(c) 8%
(d) 6.5%

Q5. A dealer offers a discount of 10% on the marked price of an article and still makes a profit of 20%. If its marked price is Rs. 800, then the cost price of the article is:
(a) Rs. 900
(b) Rs. 800
(c) Rs. 700
(d) Rs. 600

Q6. The marked price of an article is Rs. 200. A discount of 12 1/2% is allowed on the marked price and a profit of 25% is made. The cost price of the article is
(a) Rs. 200
(b) Rs. 175
(c) Rs. 120
(d) Rs. 140

Q7. A trader marked the selling price of an article at 10% above the cost price. At the time of selling he allows certain discount and suffers a loss of 1%. He allowed the discount of:
(a) 11%
(b) 10%
(c) 9%
(d) 10.5%

Q8. The marked price of an electric iron is Rs. 690. The shopkeeper allows a discount of 10% and gains 8%. If no discount is allowed, his gain percent would be
(a) 20%
(b) 24%
(c) 25%
(d) 28%

Q9. A trader marked the price of his commodity so as to include a profit of 25%. He allowed discount of 16% on the marked price. His actual profit was:
(a) 5%
(b) 9%
(c) 16%
(d) 25%

Q10. A shopkeeper marks his sarees at 20% above the cost price and allows the purchaser a discount of 10% for cash buying. What profit percent does he marked?
(a) 18%
(b) 12%
(c) 10%
(d) 8%
Solutions

S1. Ans.(d)
Sol. (x+y)-(xy/100)
(10+30)-(30 × 10/100)
40 – 3
= 37%

S3. Ans.(c)

Sol. 39=x × (97.5/100)
975x = 39000
x=39000/975
x = 40

S4. Ans.(b)
Sol. 810= 1000 × (90/100) × ((100-D)/100)
90 = 100 – D
D = 10%

S5. Ans.(d)
Sol.
M.P = 800
S.P (After discount of 10%) = 720
C.P = (720 ×100)/120
= 600
S6. Ans.(d)
Sol.
M.P = 200
S.P (After discount of 12 1/2%) = 175
C.P = ( 175 ×100)/125
= 140