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# Maths Quiz for KVS/NVS & CTET Exams

Q1. Find the length of the longest rod that can be placed in a half of 10 m length 6 m breadth and 4 m height,
(a) 2√38 m
(b) 4√38 m
(c) 2√19m
(d) √152 m

Q2. The difference of the areas of two squares drawn on two line segments of different lengths is 32sqcm. Find the length of the greater line segment if one is longer than the other by 2 cm.
(a) 7 cm
(b) 9 cm
(c) 11 cm
(d) 16 cm

Q3. A took 15 sec. to cross a rectangular field diagonally walking at the rate of 52 m/min and B took the same time to cross the same field along its sides walking at the rate of 68 m/min. The area of the field is:
(a) 30 m^2
(b) 40 m^2
(c) 50 m^2
(d) 60 m^2

Q4. The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is
(a) 1520 m^2
(b) 2420 m^2
(c) 2480 m^2
(d) 2520 m^2

Q5. The area (in m^2) of the square which has the same perimeter as a rectangle whose length is 48 m and is 3 times its breadth is:
(a) 1000
(b) 1024
(c) 1600
(d) 1042

Q6. If the volume of two cubes are in the ratio 27 : 1, the ratio of their edge is:
(a) 3 : 1
(b) 27 : 1
(c) 1 : 3
(d) 1 : 27

Q7. The edges of a cuboid are in the ratio 1 : 2 : 3 and its surface area is 88 cm^2. The volume of the cuboid is:
(a) 48 cm^3
(b) 64 cm^3
(c) 16 cm^3
(d) 100 cm^3

Q8. The volume of two spheres are in the ratio 8 : 27. The ratio of their surface area is:
(a) 4 : 9
(b) 2 : 3
(c) 4 : 5
(d) 5 : 6

Q9. The base radii of two cylinders are in the ratio 2 : 3 and their heights are in the ratio 5 : 3. The ratio of their volumes is:
(a) 27 : 20
(b) 20 : 27
(c) 9 : 4
(d) 4 : 9

Q10. The curved surface area of a cylindrical pillar is 264 m^2 and its volume is 924 m^3 (Taking π=22/7). Find the ratio of its diameter to its height.
(a) 7 : 6
(b) 6 : 7
(c) 3 : 7
(d) 7 : 3
Solutions

S1. Ans.(d)
Sol. l = 10 m, b = 6 m, h = 4 m
Length of diagonal (longest + rod) = √(100+36+16)=√152 m

S2. Ans.(b)
Sol. Let the length of smaller line segment = x cm
The length of larger line segment = (x + 2) cm
According to question,
(x+2)^2-x^2 = 32
x^2+4x+4-x^2 = 32
x=28/4=7
The required length = x + 2
= 7 + 2
= 9 cm

S4. Ans.(d)

Sol. Let the breadth be = x m
∴ length = (23 + x) m
⇒ 2(x + 23 + x) = 206
4x = 206 – 46
x = 160/4 = 40 m
∴ length = 40 + 23 = 63 m
∴ Required area = 63 × 40
= 2520 m^2

S5. Ans.(b)
Sol. Length of rectangle = 48 m
Breadth of rectangle = 16 m
According to question,
Perimeter of square =
Perimeter of rectangle
= 2 (48 + 16)
4 × side = 2 × 64
Side = (2 × 64)/4 = 32 m
∴ Area of the square
= (side)^2=(32)^2
= 1024

S6. Ans.(a)
Sol. We are given that volume of two cube are in the ratio = 27 : 1
(a1/a2 )^3=27/1
a1/a2 =∛(27/1)
=3/1
= 3 : 1

S7. Ans.(a)
Sol. Ratio of edges of cuboid = 1 : 2 : 3
Let, l = x, b = 2x, h = 3x
Surface area = 88 cm^2
2 (lb + bh + hl) = 88
2 (2x^2+6x^2+3x^2 ) = 88
11x^2 = 44
x^2 = 4
x = 2
∴ l = 2 cm, b = 4 cm, h = 6 cm
∴ Volume = lbh
= 2 × 4 × 6
= 48 cm^3